So does bash 3.2.48 and dash 0.5.7:
but ksh93u:
They employ different tie-braking rules for rounding of half-integers: "round half up" vs. "round half to even". It is tie-breaking since for example 1.5 is as far removed from 1 as it is from 2.
HI!
What is the notation which correspond to C's
doubleandfloatin Perl??
Please tell me.
Thanks.
Well what I want to do is, for example, calculatingsqrt(2)in two way: float and double. (5 Replies)
Hello
I am getting this very annoying issue in awk:
awk '{a=12825;b=a*1.25; print b}' test
16031.2
Thing is the multiplication result is wrong... Result should be 16031.25.
I think the issue only happens on bigger numbers.
What can I do to get passed this?
Thanks by advance (3 Replies)
Hi Guys,
I am generating a statistical report , below is the snippet of the code :
Now, $nSlices stands for the time duration,meaning,the statistics will be displayed for that particular time duration. Trouble is, for certain values of $totalTime (which is the end time - start time ), i... (9 Replies)
Hi
I'm using awk to manipulate the data in the 6th field of the file xxx_yyy.hrv.
The sample data that is available in this field is given below
220731.7100000000000000
When i tried using this command
cat xxx_yyy.hrv | awk '{printf("%23.16f\n",$6*-1)}'
I get the output as... (4 Replies)
Hi Friends,
I am trying to round following number.
0.07435000
echo "0.07435000"|awk '{printf "%s\n",$1*100}'|awk '{printf "%.2f\n",$1}'
It returns: 7.435
It should return: 7.44
Any suggestion please?
Thanks,
Prashant (2 Replies)
Is there a way I can round time in perl to the nearest five minutes?
For example if I have log giving the following time stamps
23,52,30 it would rounded up to 23,55,00
and
23,50,01 would be rounded to 23,50,00 (3 Replies)
Hi,
I have managed to round up numbers by using the following command:
echo "5.54" | awk '{printf "%.0f\n", $1}'
result
6
How can I round up all the numbers in a column in a file and print the lines with the new calculated totals?
Thanks, (3 Replies)
Hello,
I am using bash shell on Linux OS, May i please know why is it rounding for big numbers but not for others, is there a workaround to print it as it is with out round off?
printf '%'\''.2f\n' 9999999999999999999.99
10,000,000,000,000,000,000.00
printf '%'\''.2f\n' 99999999999999.99... (1 Reply)
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)
Discussion started by: sea
9 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)