could someone throw some light on the following behaviour of printf (I'll start with info about the system and the tool/shell/interpreter versions)?:
Only the printf builtin in ksh93t+ seems to give me what I expect (4.5 being rounded to 5 and 5.5 to 6).
Why so? And if this has anything to do with the internal representation of numbers, why does ksh93t+ make an exception?
Last edited by elixir_sinari; 10-14-2012 at 12:48 AM..
HI!
What is the notation which correspond to C's
doubleandfloatin Perl??
Please tell me.
Thanks.
Well what I want to do is, for example, calculatingsqrt(2)in two way: float and double. (5 Replies)
Hello
I am getting this very annoying issue in awk:
awk '{a=12825;b=a*1.25; print b}' test
16031.2
Thing is the multiplication result is wrong... Result should be 16031.25.
I think the issue only happens on bigger numbers.
What can I do to get passed this?
Thanks by advance (3 Replies)
Hi Guys,
I am generating a statistical report , below is the snippet of the code :
Now, $nSlices stands for the time duration,meaning,the statistics will be displayed for that particular time duration. Trouble is, for certain values of $totalTime (which is the end time - start time ), i... (9 Replies)
Hi
I'm using awk to manipulate the data in the 6th field of the file xxx_yyy.hrv.
The sample data that is available in this field is given below
220731.7100000000000000
When i tried using this command
cat xxx_yyy.hrv | awk '{printf("%23.16f\n",$6*-1)}'
I get the output as... (4 Replies)
Hi Friends,
I am trying to round following number.
0.07435000
echo "0.07435000"|awk '{printf "%s\n",$1*100}'|awk '{printf "%.2f\n",$1}'
It returns: 7.435
It should return: 7.44
Any suggestion please?
Thanks,
Prashant (2 Replies)
Is there a way I can round time in perl to the nearest five minutes?
For example if I have log giving the following time stamps
23,52,30 it would rounded up to 23,55,00
and
23,50,01 would be rounded to 23,50,00 (3 Replies)
Hi,
I have managed to round up numbers by using the following command:
echo "5.54" | awk '{printf "%.0f\n", $1}'
result
6
How can I round up all the numbers in a column in a file and print the lines with the new calculated totals?
Thanks, (3 Replies)
Hello,
I am using bash shell on Linux OS, May i please know why is it rounding for big numbers but not for others, is there a workaround to print it as it is with out round off?
printf '%'\''.2f\n' 9999999999999999999.99
10,000,000,000,000,000,000.00
printf '%'\''.2f\n' 99999999999999.99... (1 Reply)
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)