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Top Forums Shell Programming and Scripting I need to know how to replace a line after a pattern match with an empty line using SED Post 302713545 by sags007_99 on Thursday 11th of October 2012 01:12:16 AM
Old 10-11-2012
I need to know how to replace a line after a pattern match with an empty line using SED

Code:
Hi How Are you?
I am doing fine!
I need to go now?
I will see you tomorrow!

Basically I need to replace the entire line containing "doing" with a blank line:
I need to the following output:
Code:
Hi How Are you?

I need to go now?
I will see you tomorrow!

Thanks in advance....
 

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CALENDAR(1)						      General Commands Manual						       CALENDAR(1)

NAME
calendar - reminder service SYNOPSIS
calendar [-] [-r] OPTIONS
- Work for every user and send mail to him -r Restrict multiple execution on the same day EXAMPLES
calendar # Check calendar file in current directory calendar # Normary used under the control of cron(8) calendar -r # Normary used in /etc/rc file DESCRIPTION
Basically calendar program consults the file calendar in the current directory and display lines which contain today's or tomorrow's date. Month-day formats such as '12/25', 'Dec. 25', 'december 25', '*/25', '12/*', '*/*' are recognized. The asterisk means 'all' days or 'all' months. On weekends 'tomorrow' extends through next Monday without any consideration about holidays. To prevent ambiguity, the formats '25 Dec.' and '25/12' are not recognized. When an argument - is present, calendar works for all users with a file calendar in their login directories and sends them mail. Normally this is done daily under the control of cron. The -r option does its the same job as - option, but touches the calendar to prevents further access on the same day. Normally this is done in the /etc/rc file on a machine which may be booted several times in one day. SEE ALSO
cron(8). CALENDAR(1)
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