Sponsored Content
Full Discussion: Passing variables into AWK
Top Forums Shell Programming and Scripting Passing variables into AWK Post 302713127 by Boomn4x4 on Wednesday 10th of October 2012 10:01:00 AM
Old 10-10-2012
Thanks, that saved some trouble, however, my output is putting out literal text, not the variable value. My output:

myip1 myhost1.test.com myhost1
myip2 myhost2.test.com myhost2
myip1 myhost1.test.com myhost1
myip2 myhost2.test.com host2
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Passing Variables to AWK

Does anybody have an explanation for the following: The following scripts runs fine on IRIX64 6.5 but has bugs on Solaris 8. #! /bin/sh echo run only on an SGI machine echo type in linenumber read j echo value read value awk -f rmspass2 level=$value $j'step1.mlf' When the script is... (5 Replies)
Discussion started by: AreaMan
5 Replies

2. Shell Programming and Scripting

Passing Variables to Awk

Hi I have a unix shell script with an awk statement. I would like to print some of the fields of an input file. However, I would like to print them dynamically, ie by passing the literal $1 $3 into the script to define the output. I have tried the following: variable1='$1' awk... (2 Replies)
Discussion started by: Bab00shka
2 Replies

3. Shell Programming and Scripting

Passing awk Variables

I am trying to pass the results from a variable gathered from awk, however when I echo the 'PARSE' and 'SUB', the response is blank. This is my command. awk -F= '/Unit/''{ PARSE=substr($2,1,5) ; SUB=substr($2,1,1) }' inputfile.lst Is this a kind of valid attempt or am I obligated to declare... (3 Replies)
Discussion started by: gozer13
3 Replies

4. Shell Programming and Scripting

Passing space seprated variables in awk

Hi, How to pass space seprated variables in awk. (HP-UX, sh shell) I have the problem like below: var="Hello" var2="Manu Batham" echo $var2 | awk -v variable=${var} '{ printf "%s %s", variable, $1}' and its output is: Hello Manu while output should be: Hello Manu Batham Please... (4 Replies)
Discussion started by: manubatham20
4 Replies

5. Shell Programming and Scripting

Passing awk variables to shell

Hi. I need to parse file and assign some values to variables, right now i do like below MYHOMEDIR=`awk '/Home/ {print $NF}' output.txt` MYSHELL=`awk '/Shell/ {print $NF}' output.txt` PRGRP=`awk '/Primary/ {print $NF}' output.txt` SECGRP=`awk '/Second/ {print $NF}' output.txt` In this... (10 Replies)
Discussion started by: urello
10 Replies

6. Shell Programming and Scripting

ksh passing to awk multiple dyanamic variables awk -v

Using ksh to call a function which has awk script embedded. It parses a long two element list file, filled with text numbers (I want column 2, beginning no sooner than line 45, that's the only known thing) . It's unknown where to start or end the data collection, dynamic variables will be used. ... (1 Reply)
Discussion started by: highnthemnts
1 Replies

7. Shell Programming and Scripting

PAssing variables to awk arithmetic

Hi all, I am wanting to pass variables from a file to an awk arithmetic formula. When I use the formula with the value it works well. As soon as I make these variables I get an inf (infinity) response. I can certainly echo the variables back and they look correct. My googling for answers has... (3 Replies)
Discussion started by: gafoleyo73
3 Replies

8. Shell Programming and Scripting

Passing variables to awk

Hi guys, I need to fetch data from logfile between two given dates,i got the below code from our forum.It works perfect,but i need to enter the value dynamically to awk while running. awk '/2012 Jun/{p=1}!/2012 Jul/ && prev~/2012 Jul/ && p{p=0}{prev=$0}p' file i tried the below code,but... (4 Replies)
Discussion started by: mohanalakshmi
4 Replies

9. Shell Programming and Scripting

Passing awk variables to bash variables

Trying to do so echo "111:222:333" |awk -F: '{system("export TESTO=" $2)}'But it doesn't work (2 Replies)
Discussion started by: urello
2 Replies

10. Shell Programming and Scripting

awk - passing variables in and out

Am looking to pass some Linux environment variables into AWK , can I simply use the -v option ? awk -F: -v AHOME=$HOME '{ if {rm AHOME/file.txt a=2 } }' config.txt ... (4 Replies)
Discussion started by: alldbest
4 Replies
Dist::Zilla::App::Command::test(3pm)			User Contributed Perl Documentation		      Dist::Zilla::App::Command::test(3pm)

NAME
Dist::Zilla::App::Command::test - test your dist VERSION
version 4.300020 SYNOPSIS
dzil test [ --release ] [ --no-author ] [ --automated ] [ --all ] DESCRIPTION
This command is a thin wrapper around the test method in Dist::Zilla. It builds your dist and runs the tests with the AUTHOR_TESTING environment variable turned on, so it's like doing this: export AUTHOR_TESTING=1 dzil build --no-tgz cd $BUILD_DIRECTORY perl Makefile.PL make make test A build that fails tests will be left behind for analysis, and dzil will exit a non-zero value. If the tests are successful, the build directory will be removed and dzil will exit with status 0. OPTIONS
--release This will run the test suite with RELEASE_TESTING=1 --automated This will run the test suite with AUTOMATED_TESTING=1 --no-author This will run the test suite without setting AUTHOR_TESTING --all Equivalent to --release --automated --author AUTHOR
Ricardo SIGNES <rjbs@cpan.org> COPYRIGHT AND LICENSE
This software is copyright (c) 2012 by Ricardo SIGNES. This is free software; you can redistribute it and/or modify it under the same terms as the Perl 5 programming language system itself. perl v5.14.2 2012-06-21 Dist::Zilla::App::Command::test(3pm)
All times are GMT -4. The time now is 09:44 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy