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Top Forums Shell Programming and Scripting Compare values of hashes of hash for n number of hash in perl without sorting. Post 302713123 by asak on Wednesday 10th of October 2012 09:55:54 AM
Old 10-10-2012
Error Compare values of hashes of hash for n number of hash in perl without sorting.

Hi,

I have an hashes of hash, where hash is dynamic, it can be n number of hash. i need to compare data_count values of all .
Code:
my %result (
		$abc => {
				 'data_count' => '10',
				 'ID'		  => 'ABC122',
				}
				
		$def => {
				 'data_count' => '20',
				 'ID'		  => 'defASe',
				 }
				 
		:
		:
		:
		
		$n	=> {
				 'data_count' => '20',
				 'ID'		  => 'nsnsn',
			   }
		);

I need to compare the data_count of each hashes of hash, i need to get greater data_count and ID and also lesser( minimum ) data_count and ID.

how to compare the hash values without sorting using perl.

Regards,
asak
 

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Tie::RefHash(3pm)					 Perl Programmers Reference Guide					 Tie::RefHash(3pm)

NAME
Tie::RefHash - use references as hash keys SYNOPSIS
require 5.004; use Tie::RefHash; tie HASHVARIABLE, 'Tie::RefHash', LIST; tie HASHVARIABLE, 'Tie::RefHash::Nestable', LIST; untie HASHVARIABLE; DESCRIPTION
This module provides the ability to use references as hash keys if you first "tie" the hash variable to this module. Normally, only the keys of the tied hash itself are preserved as references; to use references as keys in hashes-of-hashes, use Tie::RefHash::Nestable, included as part of Tie::RefHash. It is implemented using the standard perl TIEHASH interface. Please see the "tie" entry in perlfunc(1) and perltie(1) for more informa- tion. The Nestable version works by looking for hash references being stored and converting them to tied hashes so that they too can have refer- ences as keys. This will happen without warning whenever you store a reference to one of your own hashes in the tied hash. EXAMPLE
use Tie::RefHash; tie %h, 'Tie::RefHash'; $a = []; $b = {}; $c = *main; $d = "gunk"; $e = sub { 'foo' }; %h = ($a => 1, $b => 2, $c => 3, $d => 4, $e => 5); $a->[0] = 'foo'; $b->{foo} = 'bar'; for (keys %h) { print ref($_), " "; } tie %h, 'Tie::RefHash::Nestable'; $h{$a}->{$b} = 1; for (keys %h, keys %{$h{$a}}) { print ref($_), " "; } AUTHOR
Gurusamy Sarathy gsar@activestate.com VERSION
Version 1.30 SEE ALSO
perl(1), perlfunc(1), perltie(1) perl v5.8.0 2002-06-01 Tie::RefHash(3pm)
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