If you can decompose the installed user ids and each gid into lines in a simple file, and do the same for the desired user ids and gid, then you can sort them and pass them to comm to find out what is missing. On bash, and ksh on systems with /dev/fd/[0-9]*, you can pipe it all and have less clutter and selay:
Hi,
can somebody tell me how to make directoriy in which all files will be generated as dir owner ?
I'm able to add GID for directory group and files have group id like folder , but when i do same for user files still are created as user which creates them :(
drwsrwsrwx 2 flexbul ... (2 Replies)
rm: Unable to remove directory /mnt/users/test/logs/: File exists
ls -latr
total 191208
drwxrwxrwx 6 test echo 4096 Jul 3 22:36 ..
-rwxrwxrwx 1 test echo 97692804 Jul 3 22:36 .nfsDFA4
drwxrwxr-x 2 test echo 4096 Jul 3 23:00 .
M not able to delete... (4 Replies)
I will have to process multiple files with same name everyday.
My requirement is:
If on a certain day I see that filename.txt exists then the contents of the filename.txt would be added/append
to the former file contents.Each time it sees the file the content would be added.But the header ... (8 Replies)
Hi there,
One can easily retrieve the uid from a username :
id -u $username
But how can we easily retrieve the gid from a group name?
I mean is there a command without using sed?
sed -nr "s/^$groupname:x:(+):.*/\1/p" /etc/group
Thanks for your help
Santiago (7 Replies)
Present
/home/dsadm# id dsadm
uid=0(root) gid=0(root)
----------------------------------
needs to be
/home/dsadm> id dsadm
uid=23186(dsadm) gid=16284(gdstage)
Please provide the command/steps for the above uid, gid value change
Thanks in advance for all your support .
... (3 Replies)
Hi
#Testing for file existence
if ; then
echo 'SCHOOL data is available for processing'
else
echo 'SCHOOL DATA IS NOT AVAILABLE FOR PROCESSING'
:
i wrote a script, where it begins by checking if file exists or not.
If it exists, it truncates the database... (2 Replies)
I need to list users in /etc/passwd with root's GID or UID or /root as home directory
If we have these entries in /etc/passwd
root:x:0:0:root:/root:/bin/bash
rootgooduser1:x:100:100::/home/gooduser1:/bin/bash
baduser1:x:0:300::/home/baduser1:/bin/bash... (6 Replies)
I would like to get an opinion for my solution for this task and get feedback about better approach or mistakes I have made.
1. The problem statement, all variables and given/known data:
The task is to create a script which prints information about users whose names are specified in the... (2 Replies)
Discussion started by: kornfan
2 Replies
LEARN ABOUT CENTOS
comm
COMM(1) User Commands COMM(1)NAME
comm - compare two sorted files line by line
SYNOPSIS
comm [OPTION]... FILE1 FILE2
DESCRIPTION
Compare sorted files FILE1 and FILE2 line by line.
With no options, produce three-column output. Column one contains lines unique to FILE1, column two contains lines unique to FILE2, and
column three contains lines common to both files.
-1 suppress column 1 (lines unique to FILE1)
-2 suppress column 2 (lines unique to FILE2)
-3 suppress column 3 (lines that appear in both files)
--check-order
check that the input is correctly sorted, even if all input lines are pairable
--nocheck-order
do not check that the input is correctly sorted
--output-delimiter=STR
separate columns with STR
--help display this help and exit
--version
output version information and exit
Note, comparisons honor the rules specified by 'LC_COLLATE'.
EXAMPLES
comm -12 file1 file2
Print only lines present in both file1 and file2.
comm -3 file1 file2
Print lines in file1 not in file2, and vice versa.
GNU coreutils online help: <http://www.gnu.org/software/coreutils/> Report comm translation bugs to <http://translationproject.org/team/>
AUTHOR
Written by Richard M. Stallman and David MacKenzie.
COPYRIGHT
Copyright (C) 2013 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>.
This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law.
SEE ALSO join(1), uniq(1)
The full documentation for comm is maintained as a Texinfo manual. If the info and comm programs are properly installed at your site, the
command
info coreutils 'comm invocation'
should give you access to the complete manual.
GNU coreutils 8.22 June 2014 COMM(1)