Hi,
can somebody tell me how to make directoriy in which all files will be generated as dir owner ?
I'm able to add GID for directory group and files have group id like folder , but when i do same for user files still are created as user which creates them :(
drwsrwsrwx 2 flexbul ... (2 Replies)
rm: Unable to remove directory /mnt/users/test/logs/: File exists
ls -latr
total 191208
drwxrwxrwx 6 test echo 4096 Jul 3 22:36 ..
-rwxrwxrwx 1 test echo 97692804 Jul 3 22:36 .nfsDFA4
drwxrwxr-x 2 test echo 4096 Jul 3 23:00 .
M not able to delete... (4 Replies)
I will have to process multiple files with same name everyday.
My requirement is:
If on a certain day I see that filename.txt exists then the contents of the filename.txt would be added/append
to the former file contents.Each time it sees the file the content would be added.But the header ... (8 Replies)
Hi there,
One can easily retrieve the uid from a username :
id -u $username
But how can we easily retrieve the gid from a group name?
I mean is there a command without using sed?
sed -nr "s/^$groupname:x:(+):.*/\1/p" /etc/group
Thanks for your help
Santiago (7 Replies)
Present
/home/dsadm# id dsadm
uid=0(root) gid=0(root)
----------------------------------
needs to be
/home/dsadm> id dsadm
uid=23186(dsadm) gid=16284(gdstage)
Please provide the command/steps for the above uid, gid value change
Thanks in advance for all your support .
... (3 Replies)
Hi
#Testing for file existence
if ; then
echo 'SCHOOL data is available for processing'
else
echo 'SCHOOL DATA IS NOT AVAILABLE FOR PROCESSING'
:
i wrote a script, where it begins by checking if file exists or not.
If it exists, it truncates the database... (2 Replies)
I need to list users in /etc/passwd with root's GID or UID or /root as home directory
If we have these entries in /etc/passwd
root:x:0:0:root:/root:/bin/bash
rootgooduser1:x:100:100::/home/gooduser1:/bin/bash
baduser1:x:0:300::/home/baduser1:/bin/bash... (6 Replies)
I would like to get an opinion for my solution for this task and get feedback about better approach or mistakes I have made.
1. The problem statement, all variables and given/known data:
The task is to create a script which prints information about users whose names are specified in the... (2 Replies)
Discussion started by: kornfan
2 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)