Hi Everyone,
I am a bit new at learning this bash syntax. I have a problem at work that needs to be addressed. We find we are spending quite a bit of time killing old processes created by oracle replication that have been restarted later in the week. Because the replication takes time to complete (in days) I want to kill those processes that are 4 days and older.
I found this bit of code that will work just fine but I can’t seem to hook it up to my ps statement and I am at a loss as how to do this.
NOTE: the grep word “hald” is actually one of the linux processes. Something to work with.
There are two variables the first one (print $2) is the pid and the second is the date ($9). The numbers 2 and 9 are the columns numbered left to right. That output looks like this:
I am trying to pass in the date ($9) to the “todate” but am getting confused with the available formatting.
Once I get this to work returning the number of days then I can test it and issue the kill command for the associated pid ($2).
Running the code alone with the dates already there works fine.
The default date format is the following: Tue Oct 2 14:04:31 PDT 2012 . All I want is the day which is represented by date +%d and this returns 02. How can I represent $9 as date +%d ??
Any reference book recommended for reading would be appreciated.
Hi
I need to pass a date argument with my shell script. Can any one send me code for the same.
eg For 15th Aug 2006. Iwant to pass parameter like this
./startenv.sh 08/15/2006.
Everyday date argument must change. Will the below code work ?
./startenv.sh date '+%m/%d/%y'
THanks... (1 Reply)
Hi All,
I have a crontab entry for every 5 min running.
5 * * * * /tmp/scripts/ksh/CsVues_H.sh `date +%Y%m%d_%H` >> /tmp/scripts/ksh/Cronresult.log
and I am passing the date parameter. ( `date +%Y%m%d_%H` )
But the parameter values which i am expecting inside the script is... (6 Replies)
I am following the tread number 81556 to grep a file and send the results in email.
#/bin/bash
/bin/grep -i 'invite sip' /var/log/asterisk/full
if echo "found" |
mail -s 'invite sip' mail@gmail.com
When I just build it to grep and mail, it works fine. However, the if statement causes... (4 Replies)
Hi,
Anyone can help me on how to solve my problem not getting the actual $DATE saying . Here my scripts;
#!/bin/sh
DATE='20110331'
sftp -oUserKnownHostsFile=/.ssh/known_hosts -oIdentityFile=/.ssh/id_rsa -b /source/transfer.sh server1@sftp.com <<EOF
#tranfer.sh
put... (3 Replies)
Im trying to pass curl a list of arguments... one of which is a date... When I run from the command line it works fine but when i try to run the same from a script passing variables it reformats the date for some reason and doesn't work. Example:
curlstring=xxxxxxxxxxx.xxx.xxx:8090/csv/... (1 Reply)
Dear Friends,
I need your help once again.
I have a flat file from which I have grepped something and kept in a separate file for some reason. I want to replace these grepped srtings with the strings in another file.
E.g.
Actual_file.txt
COLOR: 33179 Lakme SEPT2011
Lot No: BR25324
... (5 Replies)
Hi All....
I need to pass date into awk and parse logfile based on that.... i used both awk and /usr/xpg4/bin/awk... both are throwing up error.....
So here is the stuff...
when i use /usr/xpg4/bin/awk :
DATE=`date '+%Y %b %d'`
START=00
END=23
/usr/xpg4/bin/awk -v DATE={"$DATE"} -v... (3 Replies)
I want get a number(ID) from a sentence which has been grepped from file using error number.
For Example:
#!/bin/ksh
echo "Enter RRS ID: "
read rrs
echo "Enter error number:"
read err
scp -pr ptc-avdbamdw102:/home/icsprd/M3logs/Accurate/logs/corp_post/$rrs.*.err.txt $HOME/daemon_mail/... (7 Replies)
Greetings all,
If I have a SH script that calls a PERL script in the following way:
perl $HOME/scripts/config.properties
And in the config.properties PERL file, this Perl script only sets a number of environmental parameters in the following way:
#!/usr/bin/perl
$VAR1 = (
... (3 Replies)
We have C shell and we are executing the below script:
#!/bin/csh -f
if ($#argv != 2) then
echo "Usage $0 DirecotryPath Inputfilename"
exit 1
endif
set dir=$1
set fname=$2
echo $dir
foreach line ( `cat $fname` )
echo \ ======================================== >>... (2 Replies)
Discussion started by: donisback
2 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)
10-02-2012
