Hi Everyone,
I am a bit new at learning this bash syntax. I have a problem at work that needs to be addressed. We find we are spending quite a bit of time killing old processes created by oracle replication that have been restarted later in the week. Because the replication takes time to complete (in days) I want to kill those processes that are 4 days and older.
I found this bit of code that will work just fine but I can’t seem to hook it up to my ps statement and I am at a loss as how to do this.
NOTE: the grep word “hald” is actually one of the linux processes. Something to work with.
There are two variables the first one (print $2) is the pid and the second is the date ($9). The numbers 2 and 9 are the columns numbered left to right. That output looks like this:
I am trying to pass in the date ($9) to the “todate” but am getting confused with the available formatting.
Once I get this to work returning the number of days then I can test it and issue the kill command for the associated pid ($2).
Running the code alone with the dates already there works fine.
The default date format is the following: Tue Oct 2 14:04:31 PDT 2012 . All I want is the day which is represented by date +%d and this returns 02. How can I represent $9 as date +%d ??
Any reference book recommended for reading would be appreciated.
Hi
I need to pass a date argument with my shell script. Can any one send me code for the same.
eg For 15th Aug 2006. Iwant to pass parameter like this
./startenv.sh 08/15/2006.
Everyday date argument must change. Will the below code work ?
./startenv.sh date '+%m/%d/%y'
THanks... (1 Reply)
Hi All,
I have a crontab entry for every 5 min running.
5 * * * * /tmp/scripts/ksh/CsVues_H.sh `date +%Y%m%d_%H` >> /tmp/scripts/ksh/Cronresult.log
and I am passing the date parameter. ( `date +%Y%m%d_%H` )
But the parameter values which i am expecting inside the script is... (6 Replies)
I am following the tread number 81556 to grep a file and send the results in email.
#/bin/bash
/bin/grep -i 'invite sip' /var/log/asterisk/full
if echo "found" |
mail -s 'invite sip' mail@gmail.com
When I just build it to grep and mail, it works fine. However, the if statement causes... (4 Replies)
Hi,
Anyone can help me on how to solve my problem not getting the actual $DATE saying . Here my scripts;
#!/bin/sh
DATE='20110331'
sftp -oUserKnownHostsFile=/.ssh/known_hosts -oIdentityFile=/.ssh/id_rsa -b /source/transfer.sh server1@sftp.com <<EOF
#tranfer.sh
put... (3 Replies)
Im trying to pass curl a list of arguments... one of which is a date... When I run from the command line it works fine but when i try to run the same from a script passing variables it reformats the date for some reason and doesn't work. Example:
curlstring=xxxxxxxxxxx.xxx.xxx:8090/csv/... (1 Reply)
Dear Friends,
I need your help once again.
I have a flat file from which I have grepped something and kept in a separate file for some reason. I want to replace these grepped srtings with the strings in another file.
E.g.
Actual_file.txt
COLOR: 33179 Lakme SEPT2011
Lot No: BR25324
... (5 Replies)
Hi All....
I need to pass date into awk and parse logfile based on that.... i used both awk and /usr/xpg4/bin/awk... both are throwing up error.....
So here is the stuff...
when i use /usr/xpg4/bin/awk :
DATE=`date '+%Y %b %d'`
START=00
END=23
/usr/xpg4/bin/awk -v DATE={"$DATE"} -v... (3 Replies)
I want get a number(ID) from a sentence which has been grepped from file using error number.
For Example:
#!/bin/ksh
echo "Enter RRS ID: "
read rrs
echo "Enter error number:"
read err
scp -pr ptc-avdbamdw102:/home/icsprd/M3logs/Accurate/logs/corp_post/$rrs.*.err.txt $HOME/daemon_mail/... (7 Replies)
Greetings all,
If I have a SH script that calls a PERL script in the following way:
perl $HOME/scripts/config.properties
And in the config.properties PERL file, this Perl script only sets a number of environmental parameters in the following way:
#!/usr/bin/perl
$VAR1 = (
... (3 Replies)
We have C shell and we are executing the below script:
#!/bin/csh -f
if ($#argv != 2) then
echo "Usage $0 DirecotryPath Inputfilename"
exit 1
endif
set dir=$1
set fname=$2
echo $dir
foreach line ( `cat $fname` )
echo \ ======================================== >>... (2 Replies)
Discussion started by: donisback
2 Replies
LEARN ABOUT BSD
escape
escape(1) Mail Avenger 0.8.3 escape(1)NAME
escape - escape shell special characters in a string
SYNOPSIS
escape string
DESCRIPTION
escape prepends a "" character to all shell special characters in string, making it safe to compose a shell command with the result.
EXAMPLES
The following is a contrived example showing how one can unintentionally end up executing the contents of a string:
$ var='; echo gotcha!'
$ eval echo hi $var
hi
gotcha!
$
Using escape, one can avoid executing the contents of $var:
$ eval echo hi `escape "$var"`
hi ; echo gotcha!
$
A less contrived example is passing arguments to Mail Avenger bodytest commands containing possibly unsafe environment variables. For
example, you might write a hypothetical reject_bcc script to reject mail not explicitly addressed to the recipient:
#!/bin/sh
formail -x to -x cc -x resent-to -x resent-cc
| fgrep "$1" > /dev/null
&& exit 0
echo "<$1>.. address does not accept blind carbon copies"
exit 100
To invoke this script, passing it the recipient address as an argument, you would need to put the following in your Mail Avenger rcpt
script:
bodytest reject_bcc `escape "$RECIPIENT"`
SEE ALSO avenger(1),
The Mail Avenger home page: <http://www.mailavenger.org/>.
BUGS
escape is designed for the Bourne shell, which is what Mail Avenger scripts use. escape might or might not work with other shells.
AUTHOR
David Mazieres
Mail Avenger 0.8.3 2012-04-05 escape(1)
10-02-2012
