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Top Forums Shell Programming and Scripting Get 20% of lines in File randomly Post 302707307 by tukuyomi on Friday 28th of September 2012 10:46:49 AM
Old 09-28-2012
Here is a solution using awk:
Code:
~/unix.com$ awk 'int(100*rand())%5<1' file

5 and 1 are the parameters you want to modify here : 1/5 = 20% in this example

To be more specific in your requirements:
Code:
~/unix.com$ awk 'int(101*rand())%100<value' value=20 file | while read line; do echo "command $line"; done

Set value=... to get ...% of lines

Last edited by tukuyomi; 09-28-2012 at 12:04 PM..
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TZSELECT(8)						      System Manager's Manual						       TZSELECT(8)

NAME
tzselect - select a time zone SYNOPSIS
tzselect DESCRIPTION
The tzselect program asks the user for information about the current location, and outputs the resulting time zone description to standard output. The output is suitable as a value for the TZ environment variable. All interaction with the user is done via standard input and standard error. ENVIRONMENT VARIABLES
AWK Name of a Posix-compliant awk program (default: awk). TZDIR Name of the directory containing time zone data files (default: /usr/local/etc/zoneinfo). FILES
TZDIR/iso3166.tab Table of ISO 3166 2-letter country codes and country names. TZDIR/zone.tab Table of country codes, latitude and longitude, TZ values, and descriptive comments. TZDIR/TZ Time zone data file for time zone TZ. EXIT STATUS
The exit status is zero if a time zone was successfully obtained from the user, nonzero otherwise. SEE ALSO
newctime(3), tzfile(5), zdump(8), zic(8) TZSELECT(8)
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