I have thousands of users assigned various roles. The role header defines the GID that they should have. If I can get all the GID information into /etc/group format I can upload the output file and easily assign all users into the desired GID. Right now I can get an output file like this:
There's nothing wrong with uploading the file like this, but it's pretty big. The way I produce this is via the following function:
tmp_gid_file has a list of GID's line by line. I have to search the GID in a master file instead of getent group (it's a long story) and it returns <group_name>:<GID> so that's why I have to replace the colon with a :x:
I'd like to produce a GID file that has only 1 GID entry per line and does not duplicate. I would like it to look like this:
I started with an if statement but I have a problem appending the user's ID to the end of the line where the GID is found:
I'm using GNU/Linux (that's what I get from uname -a...not sure if it's rhel or suse or what) and my shell is bash.
Hi,
can somebody tell me how to make directoriy in which all files will be generated as dir owner ?
I'm able to add GID for directory group and files have group id like folder , but when i do same for user files still are created as user which creates them :(
drwsrwsrwx 2 flexbul ... (2 Replies)
rm: Unable to remove directory /mnt/users/test/logs/: File exists
ls -latr
total 191208
drwxrwxrwx 6 test echo 4096 Jul 3 22:36 ..
-rwxrwxrwx 1 test echo 97692804 Jul 3 22:36 .nfsDFA4
drwxrwxr-x 2 test echo 4096 Jul 3 23:00 .
M not able to delete... (4 Replies)
I will have to process multiple files with same name everyday.
My requirement is:
If on a certain day I see that filename.txt exists then the contents of the filename.txt would be added/append
to the former file contents.Each time it sees the file the content would be added.But the header ... (8 Replies)
Hi there,
One can easily retrieve the uid from a username :
id -u $username
But how can we easily retrieve the gid from a group name?
I mean is there a command without using sed?
sed -nr "s/^$groupname:x:(+):.*/\1/p" /etc/group
Thanks for your help
Santiago (7 Replies)
Present
/home/dsadm# id dsadm
uid=0(root) gid=0(root)
----------------------------------
needs to be
/home/dsadm> id dsadm
uid=23186(dsadm) gid=16284(gdstage)
Please provide the command/steps for the above uid, gid value change
Thanks in advance for all your support .
... (3 Replies)
Hi
#Testing for file existence
if ; then
echo 'SCHOOL data is available for processing'
else
echo 'SCHOOL DATA IS NOT AVAILABLE FOR PROCESSING'
:
i wrote a script, where it begins by checking if file exists or not.
If it exists, it truncates the database... (2 Replies)
I need to list users in /etc/passwd with root's GID or UID or /root as home directory
If we have these entries in /etc/passwd
root:x:0:0:root:/root:/bin/bash
rootgooduser1:x:100:100::/home/gooduser1:/bin/bash
baduser1:x:0:300::/home/baduser1:/bin/bash... (6 Replies)
I would like to get an opinion for my solution for this task and get feedback about better approach or mistakes I have made.
1. The problem statement, all variables and given/known data:
The task is to create a script which prints information about users whose names are specified in the... (2 Replies)
Discussion started by: kornfan
2 Replies
LEARN ABOUT X11R4
group
GROUP(5) Linux Programmer's Manual GROUP(5)NAME
group - user group file
DESCRIPTION
The /etc/group file is a text file that defines the groups on the system. There is one entry per line, with the following format:
group_name:password:GID:user_list
The fields are as follows:
group_name the name of the group.
password the (encrypted) group password. If this field is empty, no password is needed.
GID the numeric group ID.
user_list a list of the usernames that are members of this group, separated by commas.
FILES
/etc/group
BUGS
As the 4.2BSD initgroups(3) man page says: no one seems to keep /etc/group up-to-date.
SEE ALSO chgrp(1), gpasswd(1), groups(1), login(1), newgrp(1), sg(1), getgrent(3), getgrnam(3), gshadow(5), passwd(5)COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the
latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.
Linux 2016-10-08 GROUP(5)