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Full Discussion: wildcard in regex for awk
Top Forums Shell Programming and Scripting wildcard in regex for awk Post 302704175 by black_fender on Friday 21st of September 2012 06:34:02 AM
Old 09-21-2012
wildcard in regex for awk
Hello I have a file like :

Code:
20120918000001413 | 1.17.163.89 | iSelfcare | MSISDN | N 
20120918000001806 | 1.33.27.100 | iSelfcare | 5564 | N
....

I want to extract all lines that have on 4th field (considering "|" the separator ) something other than just digits. I want to do this using a awk one-liner ( I don;t want shell commands because combination of grep, while, cut.. etc takes way too much time)

I have this command :

Code:
awk -F'|' '$4 == " [A-Z]* "' target_file.txt

But it doesn't work.
Last edited by Scrutinizer; 09-21-2012 at 11:16 AM.. Reason: code tags also for data sample
 

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LEARN ABOUT POSIX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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