In a few folders, the files are saved with file names as given below [ends with .dat] , in this case I do not need to cut off .trnsfr.gz and also I want to extract FILE_IDs from these files along with other files whose extension end with .dat.trnsfr.gz
There is a possibility of finding files that ends with following extentions, I want to extract file_id and file_name as you provided in your previous post.
I do not want to consider files that ends with .aud.trnsfr.gz and aud.trnsfr, but I want to extract file_id and file_names from the files whose file names end with .dat.trnsfr.gz and .dat
In case of files end with .dat, i do not want to cut of its tail end since it has the file name that I required. But in case files that end with .dat.trnsfr.gz , i need to cut off .trnsfr.gz
The format will be as given in the above post.
in 2012->04 ->08 folder contains files like this
but in 2012->04->01 folder contains files like this
sasmm_fsbc_durds_id00016573_t20120401000754.dat
can you please help me out? can you give end date as 20 sept 2012 and restrics data within the range of Jan 26 2012 to Sept 20 , 2012 as well?
Thanks...
So, if you change the same line I told you to change last time from:
to:
it should do what you want. I would have expected that you'd be able to make a simple change like this yourself given the suggestions you've seen in past posts on this thread.
I have a .csv file and i use the below while loop to navigate through it
But i need to loop from the second line since the first line is the header
How will i do it?? please help
while IFS=, read Filename Path size readonly
do
echo "Filename -> ${Filename}"
echo "Path -> ${Path}"
echo... (8 Replies)
Hi i have wriiten a script which fetches the data from text file, and saves in the output in a text file itself, but i want that the output should save in different columns.
I have the output like:
For Channel:response_time__24.txt
1547 data points
0.339
0.299
0.448
0.581
7.380
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Hi
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Hi Unix gurus,
Maybe it is too much to ask for but please take a moment and help me out. A very humble request to you gurus. I'm new to Unix and I have started learning Unix. I have this project which is way to advanced for me.
File format: CSV file
File has four columns with no header... (8 Replies)
Hi,
I have a text file with the following format. Some of the fields are blank.
1234 3456 23 45464 327837283232 343434
5654353 34 34343 3434345 434242
....
....
....
I need to convert this file to a CSV file, like
1234, ,23, ... (3 Replies)
Hi
I am writing a shell script to parse a CSV file , in which i am facing a problem to separate the columns . Could some one help me with it.
IN301330/00001 pvavan kumar limited xyz@ttccpp.com
IN302148/00002 PRECIOUS SECURITIES (P) LTD viash@yahoo.co.in
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Hi, all
I want to sort a csv file based on timestamp from oldest to newest and save the output as csv file itself. Here is an example of my csv file.
test.csv
SourceFile,DateTimeOriginal
/home/intannf/foto/IMG_0739.JPG,2015:02:17 11:32:21
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Hi,
I have another problem. I want to sort another csv file by the first field.
result.csv
SourceFile,Airspeed,GPSLatitude,GPSLongitude,Temperature,Pressure,Altitude,Roll,Pitch,Yaw
/home/intannf/foto5/2015_0313_090651_219.JPG,0.,-7.77223,110.37310,30.75,996.46,148.75,180.94,182.00,63.92 ... (2 Replies)
Hi All,
I have a data file and need to extract and convert it into csv format:
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