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Top Forums Shell Programming and Scripting AWK print initial record and double Post 302703711 by chrisjorg on Thursday 20th of September 2012 08:34:05 AM
Old 09-20-2012
#!/bin/bash
Code:
for((i=1;i<=200;i++))
do
 foo=`expr 0.018\*$i`
 echo $foo >> bla
done


Gives

Code:
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i
expr 0.018 \* $i

---------- Post updated at 07:34 AM ---------- Previous update was at 07:15 AM ----------

Ok, this works:

Code:
#!/bin/bash
for((i=1;i<=200;i++))
do
 echo "0.018 * $i" | bc
done

Code:
.018
.036
.054
.072
.090
.108
.126
.144
.162
.180
.198
.216
.234
.252
.270
.288
.306
.324
.342
.360
.378
.396
.414
.432
.450
.468
.486
.504
.522
.540

 

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expr(1) 						      General Commands Manual							   expr(1)

Name
       expr - evaluate expressions

Syntax
       expr arg...

Description
       The arguments are taken as an expression.  After evaluation, the result is written on the standard output.  Each token of the expression is
       a separate argument.

       The operators and keywords are listed below.  The list is in order of increasing precedence, with equal precedence operators grouped.

       expr | expr	   Yields the first expr if it is neither null nor 0.  Otherwise yields the second expr.

       expr & expr	   Yields the first expr if neither expr is null or 0.	Otherwise yields 0.

       expr relop expr	   The relop is one of < <= = != >= > and yields 1 if the indicated comparison is true, '0' if false.  The  comparison	is
			   numeric if both expr are integers, otherwise lexicographic.

       expr + expr
	    expr - expr
			   Yields addition or subtraction of the arguments.

       expr * expr
	    expr / expr
	    expr % expr
			   Yields multiplication, division, or remainder of the arguments.

       expr : expr	   The	matching  operator compares the string first argument with the regular expression second argument; regular expres-
			   sion syntax is the same as that of The (...) pattern symbols can be used to select a portion of the  first  argument.
			   Otherwise, the matching operator yields the number of characters matched ('0' on failure).

       ( expr ) 	   parentheses for grouping.

Examples
       The first example adds 1 to the Shell variable a:
       a=`expr $a + 1`
       The second example finds the file name part (least significant part) of the pathname stored in variable a,
       expr $a : '.*/(.*)' '|' $a
       Note the quoted Shell metacharacters.

Diagnostics
       The command returns the following exit codes:

       0    The expression is neither null nor '0'.

       1    The expression is null or '0'.

       2    The expression is invalid.

See Also
       ed(1), sh(1), test(1)

																	   expr(1)
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