Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Passing a variable to kill command
Top Forums Shell Programming and Scripting Passing a variable to kill command Post 302701885 by kshji on Monday 17th of September 2012 12:39:36 PM
Old 09-17-2012
xargs is nice command when you need to give some output to the next command arguments
Code:
some_command_output | xargs kill

Example kill apache processes
Code:
ps -ef | grep apache | grep -v grep | awk '{print $2}' | xargs kill

This User Gave Thanks to kshji For This Post:
sjmolloy
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Passing the command line argument in a variable

Hi, I am new to unix. Is their a way to pass the output of the line below to a variable var1. ls -1t | head -1. I am trying something like var1=ls -1t | head -1, but I get error. Situation is: I get file everyday through FTP in my unix box. I have to write a script that picks up first... (1 Reply)
Discussion started by: rkumar28
1 Replies

2. Shell Programming and Scripting

Passing a variable in SED getting command garbled

I fairly new to SED. I have tried many different variations of this line of code and even breaking it down into its components and running them separately. They work individually without variables but when I place the $todbname variable it will either inserts the text "connect to $todbname"... (3 Replies)
Discussion started by: edewerth
3 Replies

3. Shell Programming and Scripting

Passing a variable to sudo sed command

hi, dataParse(){ line="$@" name="cat /etc/passwd | grep "$line": | cut -f6 -d':'" eval $name > sam.txt 2>&1 sudo -u $line sed -n 's/data-1/&/p' $name/test.xml >> sam1.txt } Here i getting the homedir of the accounts and is set in name variable.which returns "/home/raju" which i... (3 Replies)
Discussion started by: sachin.tendulka
3 Replies

4. Shell Programming and Scripting

passing variable values to awk command

Hi, I have a situation where I have to specify a different value to an awk command, I beleive i have the gist of this done, however I am not able to get this correct. Here is what I have so far echo $id 065859555 This value occurs in a "pipe" delimited file in postition 8. Hence I would... (1 Reply)
Discussion started by: jerardfjay
1 Replies

5. Shell Programming and Scripting

Passing a variable to sed command

Hi guys, I wanted to pass a variable to the sed command which tells which line to be deleted. a=2; echo $a; sed '$ad' c.out it is throwing an error. sed: 0602-403 "$a"d is not a recognized function. I even tried "$a" and \$a.. but it is of no use. Can you please correct me... (6 Replies)
Discussion started by: mac4rfree
6 Replies

6. UNIX for Dummies Questions & Answers

Passing a command in a variable

I need to set up a strange system through which an arbitrary command is sent to a number of different servers (well, actually, VPS accounts). We have a command "vpass" that "passes" a command from the root level to resident VPS accounts. Suppose I wanted each VPS to do some trivial thing, like... (3 Replies)
Discussion started by: treesloth
3 Replies

7. Shell Programming and Scripting

passing variable to sed command not working

Hello All, I am trying to embed variable in sed command to fetch a portion of record between two pattern. This command is not working ...any suggestion on this how to place the variable in sed command to find a portion . I am using Sun OS (Solaris). Thanks JM (1 Reply)
Discussion started by: jambesh
1 Replies

8. Shell Programming and Scripting

Passing perl variable to shell command

Can we pass perl variable to shell commands. If yes, please give some example. (2 Replies)
Discussion started by: Anjan1
2 Replies

9. Shell Programming and Scripting

Passing Shell variable from file to another command

Hi all, I have a file looks like AAAA 111 BBBB 222 CCCC 333 need to pass variable value like var1=AAAA and var2=111 to another command for three times with next values. stuck over here cat file | while read line do export var1=`awk '{print $1}'` echo $var1 export var2=`cat file... (3 Replies)
Discussion started by: rakeshtomar82
3 Replies

10. UNIX for Advanced & Expert Users

Passing Variable in -mtime command

Hi, As the process of log cleanup, Im using the below command find $DIR -mtime +3 -type f -exec gzip {} \; The problem is I want to pass +3 as variable in my unix shell. I have defined ZPDATE=+3 in my properties file and calling this property file in my script. If i try the... (6 Replies)
Discussion started by: Deena1984
6 Replies

LEARN ABOUT PLAN9

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
All times are GMT -4. The time now is 08:19 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy