That could potentially be an option if I cant get this working, basically in the below script for the DATE3 variable in the script Im tryig to get it to insert the date - 7 days i.e 120912 is todays date, I want it to insert 120905
Everything I've tried from previous posts and through what I have tried myself doesn't want to work
Using the date command
how do get yesterday's date??
e.g.
date '+%b%e%Y'
July 30 2002
I need to get
July 29 2002
using the date command.
Thanx
(p.s. sorry if it's a very obvious question) (6 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hi All.
I'm using date -a to 'drift' the time forward / backwards. The question is - how do I know when its finished 'drifting' ? On some systems I have another time reference I can use but not always.
thanks (1 Reply)
Hi is it possible to give the date command like 24th July 2009
ive tried
DATE=`date "+%d%m%Y"
echo $DATE
that only replies 2009 correctly. not sure how to display the month in full or if unix knows how to do i.e 2nd, 24th, 3rd (1 Reply)
Hi
I want to get tomorrow and yesterday date from date command. My shell is KSH and server is AIX. I tried several options, but unable to do. Please help on this.
Regards
Rajesh (5 Replies)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT DEBIAN
netsds::util::datetime
NetSDS::Util::DateTime(3pm) User Contributed Perl Documentation NetSDS::Util::DateTime(3pm)NAME
NetSDS::Util::DateTime - common date/time processing routines
SYNOPSIS
use NetSDS::Util::DateTime;
print "Current date: " . date_now();
DESCRIPTION
This package provides set of routines for date and time processing.
EXPORTED FUNCTIONS
date_now_array([TIME])
Returns array of date items for given date. If source date is not set current date used.
date_now([TIME])
Return [given] date as string.
2001-12-23 14:39:53
date_now_iso8601([TIME])
Return date as ISO 8601 string.
20011223T14:39:53Z
<http://en.wikipedia.org/wiki/ISO_8601> http://www.w3.org/TR/NOTE-datetime <http://www.w3.org/TR/NOTE-datetime>
date_strip(DATE)
Trim miliseconds from date.
date_date(DATE)
Trim time part from date.
date_time(DATE)
Trim date part from date.
time_from_string($string)
Return parsed date/time structure.
date_from_string($string)
Return date from string representation.
date_inc([INCREMENT, [TIME]])
Return date incremented with given number of seconds.
date_inc_string([INCREMENT, [TIME]])
Return string representation of date incremented with given number of seconds.
EXAMPLES
None yet
BUGS
Unknown yet
SEE ALSO
Date::Parse, Date::Format
TODO
Import stuff from Wono project
AUTHOR
Valentyn Solomko <val@pere.org.ua>
Michael Bochkaryov <misha@rattler.kiev.ua>
perl v5.12.4 2011-08-27 NetSDS::Util::DateTime(3pm)