Here if you will observe the underlined code, you will find that every time the value of $var1 changes and that i am storing in added_arr_colnme[j]. Now as you can see i tried your piece of code still it is not working. i am still having values without comma appended to them in array added_arr_colnme[j]. Can you suggest something for this?
Regards
Ganesh
Last edited by Franklin52; 09-12-2012 at 04:00 AM..
Reason: Please use code tags for data and code samples
hello
A small shell scripting help..
I have a file say with 5 lines of text (text file).
At the end of everyline I need to add a comma at the end of the file.
Thanks, ST2000 (4 Replies)
I have a file like this
101223345
23232344a
1312a3441
903821224
143434324
101223345
23232344a
1312a3441
I want to insert comma in 5 digit.
it should be like
10122,3345
23232,344a
how can I do this ?
thanks
Alice... (3 Replies)
I'm attempting to create a KSH array out of a string like this: ",,,value1,value2,,"
I have created the array but I only get two elements, one for value1 and one for value2.
I have ended up with something like this but I don't like it:
set -A JUNK
xx=0
for i in $(print ",,,value1,value2,,"... (3 Replies)
Hello,
I have been stuck on this aspect of loading a comma delimited file into an array. I thought i had the syntax right, but my commands are not working the way I want them to. Basically my cut command is splitting the file up by spaces and commas. I want the cut command to ignore white spaces.... (2 Replies)
Srr for being pain her
let say i have a data in a file like this
1@1000
2@2000
4@4000
5@7770
6@8998
7@80008
i am a newbie in Unix
i need to add a comma to integer using AWK function. for example, 1,000 or 80,008
how can i do that
ps. i'm using bash shell (1 Reply)
I am in the process of creating a BASH shell scripts for a project at work. So the scenario is as such:
I have a file with each line entry separated by ':'
... (3 Replies)
hi,
i have a variable which contains some file names separated by comma. example
FNAME="abc.txt,def.txt,ghi.txt"
i want to extract each filename and store it into an array and also count the number of files in the array.
file=abc.txt
file=def.txt
file=ghi.txt
i thought of using the... (8 Replies)
Hi Experts,
Please support
I have below data in file in comma seperated, but 4th column is containing comma in between numbers, bcz of which when i tried to parse the file the column 6th value(5049641141) is being removed from the file and value(222.82) in column 5 becoming value of column6.
... (3 Replies)
Discussion started by: as7951
3 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)