09-11-2012
names[$i]=${names[$i]}","; done
Here instead of ${names[$i]} i have a variable $var1 which has different values in each iteration. I want to append comma after the value of $var1 and then store it in a array.
Is it possible?
Regards
Mrunal
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LEARN ABOUT DEBIAN
debian::control::stanza::commaseparated
Debian::Control::Stanza::CommaSeparated(3pm) User Contributed Perl Documentation Debian::Control::Stanza::CommaSeparated(3pm)
NAME
Debian::Control::Stanza::CommaSeparated - comma separated debian/control field abstraction
SYNOPSYS
my $f = Debian::Control::Stanza::CommaSeparated->new(
'Joe M <joem@there.not>');
$f->add('"Smith, Agent" <asmith@hasyou.not>, Joe M <joem@there.not>');
print $f->as_string;
# 'Joe M <joem@there.not>, "Smith, Agent" <asmith@hasyou.not>'
print "$f"; # the same
$f->sort;
DESCRIPTION
Debian::Control::Stanza::CommaSeparated abstracts handling of comma-separated list of values, often found in debian/control file fields
like Uploaders. Note that the various dependency fields in debian/control also use comma-separated values, but the Debian::Dependencies
class is more suitable for these as it is for example also capable of finding overlapping dependency declarations.
CONSTRUCTOR
new (initial values)
The initial values list is parsed and may contain strings that are in fact comma-separated lists. These are split appropriately using
Text::ParseWords' quotewords routine.
METHODS
as_string
Returns text representation of the list. A simple join of the elements by ", ".
The same function is used for overloading the stringification operation.
add @items
Adds the ginen items to the list. Items that are already present are not added, keeping the list unique.
sort
A handy method for sorting the list.
perl v5.14.2 2012-01-15 Debian::Control::Stanza::CommaSeparated(3pm)