Hi,
Is it possible to create a dynamic array in shell script. I am trying to get the list of logfiles that created that day and put it in a dynamic array. I am not sure about it. help me
New to scripting
Gundu (3 Replies)
Hi all,
i am quite fimiliar with shell scripting but i wouldn't regard myself as a semi professional at it.
I am trying to create an array variable to read in 4 lines from a file using head and tail command in a pipeline and store each line into each array. I have done the scripting in unix... (2 Replies)
i want to create an array
the array elements are populated depending upon the number of entries present in a data file
The data file is created dynamically
how to achieve the same
thanks (1 Reply)
I am facing a strange error while creating posix threads:
Given below are two snippets of code, the first one works whereas the second one gives a garbage value in the output.
Snippet 1
This works:
--------------
int *threadids;
threadids = (int *) malloc (num_threads * sizeof(int));
... (4 Replies)
I am wondering how I can save the file names (stored in $file or $fnames) in array which I can access with an index.
alias MATH 'set \!:1 = `echo "\!:3-$" | bc -l`'
set narg = $#argv
while ($iarg < $narg)
MATH iarg = $iarg + 1
set arg = $argv
set opt = ` echo $arg | awk... (1 Reply)
I have an interesting requirement. I have declaried an array like :-
arr=`find . ! -name "." | xargs -I {} echo {} | cut -c 2-${#}`
Then i will try to access the array elements like :-
i=0
for i in ${arr}; do
Here comes the confusions, the array elements are basically dir and files stored... (2 Replies)
Hi gurus,
I need to create arrays from variables, via a loop.
The issue I have is with the array name creation. How do I use a variable to define an array?
I want to do something like
declare -a $H
where $H is my loop variable.
I then need to add items to each array I've created,... (3 Replies)
I am having trouble creating an array, I've tried everything google gives me but it won't work, and it seems as though it should. Using Ubunto 12.04 and bash.
#!/bin/bash
ARRAY=one two three
echo ${ARRAY}When I do this I receive the error
: two: not found
and
: Bad substitution
When I... (3 Replies)
Hi Guys,
I am writting a c shell script where I have to parse an input argument with options that could be an array. So far I have achieved where I could parse a single argument with option but failed when I try to create an array with the options. For example:
This is on terminal window:... (2 Replies)
Discussion started by: dixits
2 Replies
LEARN ABOUT PHP
datefmt_localtime
DATEFMT_LOCALTIME(3) 1 DATEFMT_LOCALTIME(3)IntlDateFormatter::localtime - Parse string to a field-based time value
Object oriented style
SYNOPSIS
public array IntlDateFormatter::localtime (string $value, [int &$position])
DESCRIPTION
Procedural style
array datefmt_localtime (IntlDateFormatter $fmt, string $value, [int &$position])
Converts string $value to a field-based time value ( an array of various fields), starting at $parse_pos and consuming as much of the
input value as possible.
PARAMETERS
o $fmt
- The formatter resource
o $value
- string to convert to a time
o $position
- Position at which to start the parsing in $value (zero-based). If no error occurs before $value is consumed, $parse_pos will
contain -1 otherwise it will contain the position at which parsing ended . If $parse_pos > strlen($value), the parse fails immedi-
ately.
RETURN VALUES
Localtime compatible array of integers : contains 24 hour clock value in tm_hour field
EXAMPLES
Example #1
datefmt_localtime(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN
);
$arr = datefmt_localtime($fmt, 'Wednesday, December 31, 1969 4:00:00 PM PT', 0);
echo 'First parsed output is ';
if ($arr) {
foreach ($arr as $key => $value) {
echo "$key : $value , ";
}
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN
);
$arr = $fmt->localtime('Wednesday, December 31, 1969 4:00:00 PM PT', 0);
echo 'First parsed output is ';
if ($arr) {
foreach ($arr as $key => $value) {
echo "$key : $value , ";
}
}
?>
The above example will output:
First parsed output is tm_sec : 0 , tm_min : 0 , tm_hour : 16 , tm_year : 1969 ,
tm_mday : 31 , tm_wday : 4 , tm_yday : 365 , tm_mon : 11 , tm_isdst : 0 ,
SEE ALSO datefmt_create(3), datefmt_format(3), datefmt_parse(3), datefmt_get_error_code(3), datefmt_get_error_message(3).
PHP Documentation Group DATEFMT_LOCALTIME(3)