Hi all
I need command to give me the utilization for memory and cpu,and how can I know if the utilization ok or no?
for example in hp unix #top
it is give me utilize for cpu and memory and also I can know if utilize ok or no.
thanks (2 Replies)
hi guys
I just want to know how to get the cpu/memory utilization of a running script?
Well i know that I can use the sar command but it shows the whole system's statistics.
Is it possible to get the stats of a single scirpt or a single running service? (6 Replies)
I am trying to get cpu util and memory occupied for a process. I use these (I am showing output also):
using top
----------
$ top p 25272 d 5
top - 01:52:17 up 2 days, 21:28, 2 users, load average: 0.02, 0.05, 0.06
Tasks: 1 total, 0 running, 1 sleeping, 0 stopped, 0 zombie... (5 Replies)
Hi,
I would like to view the cpu and memory utilization of a given job over time and save this information in a file, such that at the end of the process I can create a plot of the CPU and memory utilization over time.
Is this possible?
I would like to do the same for the io, is there any... (1 Reply)
Hi guys,
I am new to Unix and have been asked to Check the CPU and Memory utilization using the Glance command.
I have tried searching and Google but cant find anything that makes sense to me :o
Does anyine have any links to somewhere that will explain exactly what it is - tried "man... (2 Replies)
Hi ,
We need to get the CPU% and Memory utilization of process by process id.
Is there any way to do get them ?
I tried few commands like top -p <PID> ,
but am getting error "Quitting top: pset <PID> doesn't exist"
also i tried with ps -eo option but am getting error "ps: illegal option --... (1 Reply)
Hi ,
We need to get the CPU% and Memory utilization of process by process id.
Is there any way to do get them ?
I tried few commands like top -p <PID> ,
but am getting error "Quitting top: pset <PID> doesn't exist"
also i tried with ps -eo option but am getting error "ps: illegal option --... (5 Replies)
Hi,
i am new to linux/RHEL 6.0 and i have two questions.
1) How to get the CPU utilization and Memory Utilization of all Services running currently?
2) How to get the CPU utilization and Memory Utilization of all Applications running currently?
Please help me to find the script.
... (2 Replies)
Discussion started by: nossam
2 Replies
LEARN ABOUT DEBIAN
unparse_time_approx
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL October 31, 2004 HEIMDAL