09-06-2012
What OS and shell are you using?
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.
Ramesh (1 Reply)
Discussion started by: rameshspal
1 Replies
2. Shell Programming and Scripting
I have looked through the forums and found many date / time manipulation tools, but cannot seem to find something that fits my needs for the following.
I have a log file with date time stamps like this:
Jun 21 17:21:52
Jun 21 17:24:56
Jun 21 17:27:59
Jun 21 17:31:03
Jun 21 17:34:07
Jun... (0 Replies)
Discussion started by: roadcyclist
0 Replies
3. UNIX for Dummies Questions & Answers
how can we add or subtract days from the output of date command in unix...
like if i want to subtract a day from the result of date command like this..
v_date=`date +%Y%m%d`
this wud give me 20080519
now i want to subtract one day from this.. so tht it wud give me 20080518..
how do i do... (1 Reply)
Discussion started by: St.Fartatric
1 Replies
4. UNIX for Dummies Questions & Answers
Hi Gurus!
I have a static date in a YYYYMMDD format; and I want get the date 2 years in the past and 2 years in the future.
static_date=20010203
old_date=$static_date - 3 years
future_date=$static_date + 2 years
I was only able to research on dates that are current and not on static... (3 Replies)
Discussion started by: kokoro
3 Replies
5. Shell Programming and Scripting
Hi ,
How can I add/substruct x number of days with date?
For example
My_Date=`date`
Now I need
Hope it's clear. (2 Replies)
Discussion started by: Anupam_Halder
2 Replies
6. UNIX for Dummies Questions & Answers
Hi,
Is there a way to subtract a month or at least 30 days from an arbitrary or user inputted date without the GNU date?
Example:
please Input date: 2011-05-11
then the answer will be 2011-04-11
This code doesn't work:
$date -d "2011-05-11 - 1 month" "+%Y%m%d"
Thanks (7 Replies)
Discussion started by: erin00
7 Replies
7. UNIX for Dummies Questions & Answers
Hi All,
I am using KSH shell and need to subtract n number of days from the current date .. kindly suggest !
Thanks in advance!:) (20 Replies)
Discussion started by: dev.devil.1983
20 Replies
8. Shell Programming and Scripting
Hi All,
I am getting a date from environment variable and want to do some processing by subtracting 2 months from the date passed through the environment variable.
I am trying the following syntax :
date_var=2014-08-31
date_2M_ago='$date_var+"%d%m%y" --$date_var="2 months ago" '... (3 Replies)
Discussion started by: Rahul Raj
3 Replies
9. Shell Programming and Scripting
I am trying to achieve to get only the month and the day. Example Feb 5 (as you can see if it is feb 1-9) the space is 2. If it is feb 10-28, the space is only 1. I am trying to right a script that will list a directory and shoot an email if there is an activity in last 7 days. I dont really trust... (5 Replies)
Discussion started by: invinzin21
5 Replies
10. UNIX for Beginners Questions & Answers
Hi All,
I have a CSV file which is as below. Basically I need to take the year column in it and find if the year is >= 20152 . If that is then I should subtract all values by 6. In the below example in description I am having number mentioned as YYWW so I need to subtract those by -5. Whereever... (8 Replies)
Discussion started by: arunkumar_mca
8 Replies
LEARN ABOUT CENTOS
dm_date
DM_DATE(1) User Contributed Perl Documentation DM_DATE(1)
NAME
dm_date - print out the system date and time
SYNOPSIS
This performs the same operation as the unix 'date' command, but using the Date::Manip module.
dm_date [OPTION]... [+FORMAT]
DESCRIPTION
This displays information about the current system time, or some other time. Options are:
-h, --help
Print online help.
-d STRING, --date=STRING
Display time described by STRING. STRING can be any string which can be parsed by Date::Manip. Please refer to the Date::Manip::Date
documentation for details.
-f DATEFILE, --file=DATEFILE
This reads each line in DATEFILE, and extracts a date from it and prints out the information.
Blank lines and lines starting with a pound (#) are ignored. Lines not containing a valid date are also ignored.
-r FILE, --reference=FILE
Displays the last modification time of FILE.
-R, --rfc-2822
Displayc the date and time in RFC 2822 format.
Example: Mon, 07 Aug 2006 12:34:56 -0600
-u, --utc, --universal
Converts the date to UT (GMT) and prints out the information.
Only one of -d, -f, or -r should be included. If more than one is included, the first one from the list (-d, -f, -r) is used and any other
is ignored.
The format string starts with a plus (+) and contains any of the format directives described in Date::Manip::Date.
KNOWN BUGS
None known.
BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author.
SEE ALSO
Date::Manip::Date
LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
AUTHOR
Sullivan Beck (sbeck@cpan.org)
perl v5.16.3 2014-06-09 DM_DATE(1)