Sponsored Content
Top Forums Shell Programming and Scripting [Solved] Printing a part of the last line of the specific part of a file Post 302695609 by vgersh99 on Monday 3rd of September 2012 09:04:08 AM
Old 09-03-2012
Code:
awk -F= '$1 ~ "Name" {n=$2;next} n && $1~"Value"{print n,$2;n=""} OFS== myFile

 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Reading specific part of file

I have a requirement to go to particular line in the file and from there read the contents till it meets a particular criteria. For eg if the contents of the file is like 81 abcd ------------------- Line 1 82 cdfe ------------------- Line 2 83 dfj ------------------- Line 3 84 df... (5 Replies)
Discussion started by: guptan
5 Replies

2. UNIX for Dummies Questions & Answers

Printing a part of a string

hi I have the input as follows ABC =893 JKL = "jee" alias PQR = 9833 alias STUVE = "kuiue" I should be able to print as follows ABC JKL alias PQR alias STUVE Thanks Suresh (7 Replies)
Discussion started by: ssuresh1999
7 Replies

3. UNIX for Dummies Questions & Answers

[Solved] Rename file name / remove part of name

I have a whole file structure with jpeg files where I want to remove a part of the file name. An application added in many files a case conflict in the naming "xyz 017.jpg (Case Conflict 1)" So, can someone help me how to get rid of the " (Case Conflict 1)"? What I have is this: find . -name... (2 Replies)
Discussion started by: borobudur
2 Replies

4. Shell Programming and Scripting

Change in last line of each part of a file

Hi, I have a input files as below. Sample of one input file type mtg_key = record decimal("\344") id; string("\344") ct_cd; string("\344") st_cd; end; type psl_key = record decimal("\344") id; utf8 string("\344") st_cd; end; type amk_fields = record ... (6 Replies)
Discussion started by: adgangwar
6 Replies

5. Shell Programming and Scripting

Shell script - Replace just part of a single line in a file.....

Hey guy's.... I new here, But im working on a school project, and I am not really good at programming. In fact, this is the only programming class that I need because programming is not what I am majoring in. But I have everything done in this shell script except for this last part..... ... (9 Replies)
Discussion started by: hxdrummerxc
9 Replies

6. Shell Programming and Scripting

Reading text file, comparing a value in a line, and placing only part of the line in a variable?

I need some help. I would like to read in a text file. Take a variable such as ROW-D-01, compare it to what's in one line in the text file such as PROD/VM/ROW-D-01 and only input PROD/VM into a variable without the /ROW-D-01. Is this possible? any help is appreciated. (2 Replies)
Discussion started by: xChristopher
2 Replies

7. UNIX for Dummies Questions & Answers

Grep a part of a line from a file

Hi, I have a file with thousands of lines as below INSERT INTO T_DIM_CLNT(CLNT_KY,CLNT_OBJ_ID,ISI_CLNT_ID,OPERN_ID,CLNT_NM,PRMRY_SIC_CD,PRMRY_SIC_DSC,RET_AGE_NBR,REC_CRT_TS,REC_DATA_EXTRC_TS,ETL_LOG_KY) VALUES ( ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)... (5 Replies)
Discussion started by: sudhakar T
5 Replies

8. Shell Programming and Scripting

Extract a part of variable/line content in a file

I have a variable and assigned the following values ***XYZ_201519_20150929140642_20150929140644_211_0_0_211 I need to read this variable from backward and stop read when I get first underscore (_) In this scenario I should get 211 Thanks Kris (3 Replies)
Discussion started by: mkris
3 Replies

9. Shell Programming and Scripting

How to print the specific part of the file name with file creation date?

Hello Folks, I have an requirement, where i need to get total count of the file based on creation date with there filename selected pattern. Filename: MobileProtocol.20171228T154200.157115.udr I want to get the count of files created on each day based on a pattern find. find . -type... (7 Replies)
Discussion started by: sadique.manzar
7 Replies

10. UNIX for Beginners Questions & Answers

How to make a loop to read the input from a file part by part?

Hi All, We've a VDI infrastructure in AWS (AWS workspaces) and we're planning to automate the process of provisioning workspaces. Instead of going to GUI console, and launching workspaces by selecting individual users is little time consuming. Thus, I want to create them in bunches from AWS CLI... (6 Replies)
Discussion started by: arun_adm
6 Replies
IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +--------------------+-----------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +--------------------+-----------------+ |Availability | SUNWgawk | +--------------------+-----------------+ |Interface Stability | Volatile | +--------------------+-----------------+ NOTES
Source for gawk is available on http://opensolaris.org. Free Software Foundation Nov 3 1999 IGAWK(1)
All times are GMT -4. The time now is 11:38 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy