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Full Discussion: [awk] grep a part of filename as entry file
Top Forums Shell Programming and Scripting [awk] grep a part of filename as entry file Post 302695485 by itkamaraj on Monday 3rd of September 2012 04:03:35 AM
Old 09-03-2012
Code:
$ nawk 'BEGIN{print FILENAME}' a.txt
a.txt

FILENAME - The name of the current input file. If no files are specified on the command line,the value of FILENAME is "-". However, FILENAME is undefined inside the BEGIN block (unless set by getline).

so, iterating all the csv files, you can use for loop

Code:
 
for i in *.csv
do
nawk -F"[_.]" 'BEGIN{fdate=substr(FILENAME,length(FILENAME)-14,11)}NR==4{$0=fdate","$0;print}' $i
done

This User Gave Thanks to itkamaraj For This Post:
makan
 

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