09-02-2012
Quote:
That pattern it's a directory tree path rooted at each given file name , so it's not necessarily a directory inside which find will begin its searches.
Notice that post #3's
-exec ls ... output contains duplicate filenames. There is nothing in that find command that prints a matching file name twice (and non-consecutively), and since a directory cannot contain two identically-named files, the shell
must be matching one or more directories with that pattern (in addition to *test* files in tmp, if any).
With a directory path, the
-exec predicates of those find commands will list or attempt to delete every regular file in that directory and its subdirectories, regardless of a file's name.
Quote:
It should != it must.
True, but it's preferable to be precise and avoid this type of unnecessary bug.
Regards,
Alister
Last edited by alister; 09-02-2012 at 03:24 PM..
9 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hi All,
i am writing a shell script in korn shell
which deletes all the files in a directory
once in every 10DAYS.
the directory has different format files.
the script has something like this;
cd /home/data/pavi
echo "Please Enter the Number of Days to search for"
read DAYS... (2 Replies)
Discussion started by: pavan_test
2 Replies
2. UNIX for Advanced & Expert Users
Hi,
I'm using the following command to get a list of files on the system.
find /releases -type f -exec ls -l > /home/sebarry/list.txt '{}' \;
however, its searching a directory I don't want it to search so I know I have to use prune but I don't seem to be able to get prune and exec to work... (1 Reply)
Discussion started by: Sebarry
1 Replies
3. Shell Programming and Scripting
Hi People,
I have a directory full of compressed files (.Z extention)
In many of these files there is a string pattern (3800078163033)
I want to find all file names which contain this string in their text.
Regards,
Abhishek (2 Replies)
Discussion started by: max29583
2 Replies
4. Shell Programming and Scripting
Hi
I have a little problem with the find command in a script that I'm writing. The script should check if there are some files younger than 100 seconds and then syncronise them with rsync.
My find command:
find -type f -cmin -100 -exec rsync -a --delete directory1/ directory2/
When I... (8 Replies)
Discussion started by: oku
8 Replies
5. Shell Programming and Scripting
Hello All,
Is there a way to make exec do a couple of operations on a single input from find?
For example,
find . -type d -exec ls -l "{}" ";"
I would like to give the result of each "ls -l" in the above to a wc. Is that possible?
I want to ls -l | wc -l inside exec. How do I... (1 Reply)
Discussion started by: prasanna1157
1 Replies
6. Shell Programming and Scripting
Hi all,
Please could someone help with the following command requirement.
I basically need to find files NEWER than a given file and order the result on time.
My attempt so far is as follows:
find . -newer <file_name> -exec ls -lrt {} ;\
But I dont seem to get the right result... (12 Replies)
Discussion started by: jonnyd
12 Replies
7. UNIX for Dummies Questions & Answers
Hi,
I have two scripts that remove files. One works fine and is coded
find -name "syst*" -mtime +1 -exec rm {} \;
The other is almost the same - only thing missing is the '\'. On that script though I keep getting:
rm syst1202.file ?
etc
Does the \ make that difference or is it a... (3 Replies)
Discussion started by: Grueben
3 Replies
8. Shell Programming and Scripting
Hi all,
I am trying to find files newer than a given file and them mv them to a new location.
So I far I have:
find . ! -newer <file_name> -exec ls -l {} \;
and
find . ! -newer <file_name> -exec mv /TEMP_LOCATION {} \;
find is not liking this.
Anyone know how to modify the last... (2 Replies)
Discussion started by: jonnyd
2 Replies
9. Shell Programming and Scripting
Hello.
From a script, a command for a test is use :
find /home/user_install -maxdepth 1 -type f -newer /tmp/000_skel_file_deb ! -newer /tmp/000_skel_file_end -name '.bashrc' -o -name '.profile' -o -name '.gtkrc-2.0' -o -name '.i18n' -o -name '.inputrc'
Tha command... (3 Replies)
Discussion started by: jcdole
3 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)