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Top Forums UNIX for Dummies Questions & Answers [Solved] weird in find -exec command Post 302695285 by alister on Sunday 2nd of September 2012 01:37:57 PM
Old 09-02-2012
Quote:
Originally Posted by Lem
That pattern it's a directory tree path rooted at each given file name , so it's not necessarily a directory inside which find will begin its searches.
Notice that post #3's -exec ls ... output contains duplicate filenames. There is nothing in that find command that prints a matching file name twice (and non-consecutively), and since a directory cannot contain two identically-named files, the shell must be matching one or more directories with that pattern (in addition to *test* files in tmp, if any).

With a directory path, the -exec predicates of those find commands will list or attempt to delete every regular file in that directory and its subdirectories, regardless of a file's name.


Quote:
Originally Posted by Lem
It should != it must. Smilie
True, but it's preferable to be precise and avoid this type of unnecessary bug.

Regards,
Alister

Last edited by alister; 09-02-2012 at 03:24 PM..
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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