Hello,
I am new to db2 SQL in unix so bear with me while I try to explain the situation. I have a text file that has the contents of the where condition that I am using for a db2 SQL in UNIX ksh.
Here is the snippet.
if ;
then
echo "Begin processing VALUEs"
... (1 Reply)
Hi everybody:
Could anybody tell me how I can print from a file a selected rows with awk. In my case I only want print in another file all the rows from NR=8 to NR=2459 and the increment each 8 times.
I tried to this:
awk '{for (i=8; i=2459; i+=8); NR==i}' file1 > file2
But doesn't... (6 Replies)
Hi. How do I find an expression with awk in only one column, and if it fits, then print that whole column.
1 apple oranges
2 bannanas pears
3 cats dogs
4 hesaid shesaid
echo "which number:"
read NUMBER (user inputs number 2 for this example)
awk " /$NUMBER/ {field to search is field... (2 Replies)
Looks at the most efficient way to add up the column of data based off of the rows.
Random data
Name-Number-ID
Sarah-2.0-15
Bob-6.3-15
Sally-1.0-10
James-1.0-10
Scotty-10.7-15
So I would select all those who have ID = 15 and then add up total number
read - p "Enter ID number" Num
... (3 Replies)
a,b,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z,aa,bb,cc,dd,ee,ff,gg,hh,ii
a thru ii are digits and strings....
The awk needed....if coloumn 9 == i (coloumn 9 is string ), output the sum of x's(coloumn 22 ) in all records and sum of y's (coloumn 23 ) in all records in a file (records.txt).... (6 Replies)
Hi I want to print all rows where there is the alphabet N in the 6th column as a substring.
Here is what i tried and not working.Please help !
awk ' { if ( $6 == *"N"* ) print $0} '
awk ' { if ( "${6}" == *N* ) print $0} '
awk ' { if( grep -q N <<<$6) print $0} ' (1 Reply)
Hi,
My input files is like this
axis1 0 1 10
axis2 0 1 5
axis1 1 2 -4
axis2 2 3 -3
axis1 3 4 5
axis2 3 4 -1
axis1 4 5 -6
axis2 4 5 1
Now, these are my following tasks
1. Print a first column for every two rows that has the same value followed by a string.
2. Match on the... (3 Replies)
hi,
i have a fixed width file with multiple columns and need to print data using awk command.
i use: awk -F "|" '($5 == BH) {print $1,$2,$3}' <non_AIM target>.txt for a delimiter file.
but now i have a fixed width file like below:
7518 8269511BH 20141224951050N8262
11148 8269511BH... (5 Replies)
Hello
I want to collapse a file with multiple rows into consolidated lines of entries based on selected columns as the 'key'.
Example:
1 2 3 Abc def ghi
1 2 3 jkl mno p qrts
6 9 0 mno def Abc
7 8 4 Abc mno mno abc
7 8 9 mno mno abc
7 8 9 mno j k
So if columns 1, 2 and 3 are... (6 Replies)
Example:
I have files in below format
file 1:
zxc,133,joe@example.com
cst,222,xyz@example1.com
File 2 Contains:
hxd
hcd
jws
zxc
cst
File 1 has 50000 lines and file 2 has around 30000 lines :
Expected Output has to be :
hxd
hcd
jws (5 Replies)
Discussion started by: TestPractice
5 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)