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Top Forums Shell Programming and Scripting awk command to print only selected rows in a particular column specified by column name Post 302695097 by jim mcnamara on Saturday 1st of September 2012 10:09:01 AM
Old 09-01-2012
Try this:
Code:
col="Something"
awk -v col="$col" ' NR==1 {for(i=1; i<=NF ; i++){ if($1==col) {break} } ; next}
                          {print $i} '  infile.csv

 

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DB2_FIELD_NAME(3)							 1							 DB2_FIELD_NAME(3)

db2_field_name - Returns the name of the column in the result set

SYNOPSIS
string db2_field_name (resource $stmt, mixed $column) DESCRIPTION
Returns the name of the specified column in the result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns a string containing the name of the specified column. If the specified column does not exist in the result set, db2_field_name(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_NAME(3)
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