Hi,
I have an embedded Perl construct in a korn script. However, I cannot seem to access the shell variables that were declared outside this Perl section.
This is how my script is written....I have also tried back-ticks where I assign the shell variable to my local perl variable, still... (1 Reply)
I hope I am posting this in the right section.
I have c file that is using the motif GUI toolkit to draw widgets and things of that sort. I also have another program that runs with xnest. I need to figure out a way to place that xnest program in my c code so that it exists in the window that the... (4 Replies)
Hi
I am trying to run a script centrally that will go out and set the network management ip address on all my Sun boxes running Solaris. We have decided that the network management address will be the boxes main IP address but the first octet as a 172 rather than a 10, so for example ifconfig -a... (2 Replies)
Hello,
I'm trying to run a program on a directory (traverse sub dirs too) through my csh script. Arrays support in CSH is appalling, something like associative arrays would have helped me do this so much easier.
Anyway, I want to hold some details extracted from the program and then at the... (0 Replies)
Hello.
I found a Unix script on this site that calculates a date that is 2 months earlier from today. I'm using that script and writing the value to a file called 2monthsago.txt. I want to use that value in another script. Below is my attempt at doing that and the results.
My Script:
... (1 Reply)
My webpage is hosted from perlscript(homepage.pl), i want to add piece of html code in the footer of the homepage. I simply pasted the html code at the end of the perl script as below...
========================================================
close(OUTSQL);
... (4 Replies)
Hi,
I am working on a parsing script but cannot figure out how to accomplish this. Here is a simplified version of the script:
#!/bin/bash
DS=$1
DS=`expr $DS \* 2`
DS=`expr $DS + 7`
cat $FILENAME | awk '/<row><v> +/' | awk '{printf("%.0f %.0f\n", $6, $9)}'
The problem is that I want the... (2 Replies)
Hi
Its been a long time since I worked with ssh keys containing embedded shell commands and cannot remember how it is done.
Does anyone know of any sites that have a good tutorial on the subject? I'm not having much luck searching Google for it.
Incidentally, searching this forum for the... (6 Replies)
I have 7 functions those need to be executed as command line inputs, I tried with below code it’s not executing function. If I run the ./script 2 then fun2 should execute , how to initiate that function I tried case and if else also, how to initiate function from command line
if
then... (8 Replies)
Discussion started by: saku
8 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)