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Full Discussion: dd cloning of whole disk
Operating Systems Linux Ubuntu dd cloning of whole disk Post 302691441 by Lem on Friday 24th of August 2012 02:19:15 PM
Old 08-24-2012
Quote:
In particular to explore the path system for storing the log file in an umounted drive.
What? Please...

Quote:
I have come to the conclusion that ddrescue, or the Remix version if such, is incapable of writing an output to anything other than a completely fresh i.e. empty disk.
I'm sorry, but this makes no sense. There's no difference between a completely fresh empty disk and a disk full of data, when you look at them as block devices as ddrescue does. And ddrescue works flawlessly.

You simply didn't get what's "-g" (or "--generate-logfile") for. True that the man didn't help you with too many words, I must admit. But please read here carefully:
GNU ddrescue Manual

With this "-g" option, ddrescue doesn't even try to copy: it tries to generate a logfile from a source and an already made (partial) copy.

Don't use the option "-g", and ddrescue will work for you. Smilie
HTH.
--
Bye
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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