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Shell Programming and Scripting
Need help with sed and regexp
Post 302691289 by Boxtuna on Friday 24th of August 2012 06:53:28 AM
08-24-2012
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I am using GnuWin32 sed and am having trouble with the regexp - i.e., they don't behave the same way as in UNIX (POSIX and and all that). I have a stream of data, e.g.:
11111'222?'22'33?'333'44444'55555'
I want to insert a \n after those apostrophes that are *not* preceded by a ?.
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please help:
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output file:
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The following sed command does not work:
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Hi all,
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Hi,
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When I ran the below command:
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Dear all
i have the code which print 1 line of context before and after regexp, with line number
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G'day,
Here's a teaser for a sed guru, which I surely am not one, as even my
basic sed skills are rusted from years of not practising ... lol
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LEARN ABOUT REDHAT
tzselect
TZSELECT(8) System Manager's Manual TZSELECT(8) NAME
tzselect - select a time zone SYNOPSIS
tzselect DESCRIPTION
The tzselect program asks the user for information about the current location, and outputs the resulting time zone description to standard output. The output is suitable as a value for the TZ environment variable. All interaction with the user is done via standard input and standard error. ENVIRONMENT VARIABLES
AWK Name of a Posix-compliant awk program (default: awk). TZDIR Name of the directory containing time zone data files (default: /usr/local/etc/zoneinfo). FILES
TZDIR/iso3166.tab Table of ISO 3166 2-letter country codes and country names. TZDIR/zone.tab Table of country codes, latitude and longitude, TZ values, and descriptive comments. TZDIR/TZ Time zone data file for time zone TZ. EXIT STATUS
The exit status is zero if a time zone was successfully obtained from the user, nonzero otherwise. SEE ALSO
newctime(3), tzfile(5), zdump(8), zic(8) TZSELECT(8)