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Top Forums Shell Programming and Scripting shell scripts do not exit once completed Post 302690617 by bakunin on Thursday 23rd of August 2012 07:36:57 AM
Old 08-23-2012
Quote:
Originally Posted by guddu_12
I have an issue since this database part is done in the middle of the scripts and it exit finally from the scripts, how can i make sure it does it part in data base and then execute rest of the scripts
hmm, you already know the routine: post an error message and we take a look at it. If there is no error message, start the script with "ksh -x <scriptname>" and show the relevant parts of the output (before you ask why redirection doesn't work: it goes to <stderr>).

In other words: D-E-B-U-G the script by S-E-A-R-C-H-I-N-G for the error instead of sitting there and asking us things we cannot answer (because we do not see what is on your monitor or harddisk).

My guess is that one of the "exit" statements meant for for exiting "sqlplus" is in fact directed at the shell, which would make the shell (and the script) exit. This is only an unproven suspicion, though.

I hope this helps.

bakunin
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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