I'm reading from a file that is semi-colon delimited. One of the fields contains 2 spaces separating the first and last name (4th field in - "JOHN<space><space> DOE"):
e.g. TORONTO;ONTARIO;1 YONGE STREET;JOHN DOE;CANADA
When I read this record and either echo/print to screen or write to... (4 Replies)
i have a commad that display the total each directory size in KB.Below the commad and o/p:
ls -ltr | grep ^d | awk '{print $9}' | xargs du -sk
output:
what i want is the proper tab space b/w value and dir.? how to get that.
thanks in advance (10 Replies)
Wants to print line when there exist leading or trailing space or tab in fields 2,3 and 5
The below code prints all lines in file even if they dont have leading and trailing space or tab.
nawk -F"|" '{for(i=1;i<=NF;i++) {if ($i ~ "^*" || $i ~ "*$")}}1' file
file
Ouput required:
... (5 Replies)
Hi,
So my file looks like this:
title number
JR 2
JR 2
JR 4
JR 5
NM 5
NM 8
NM 2
NM 8
I used this line that I wrote to convert it to rows so it will look like this:
awk -F"\t" '!/^$/{a=a" "$3} END {for ( i in a) {print i,a}}' occ_output.tab > test.txt
JR 2 2 4 5
NM 5 8... (4 Replies)
Hello,
Is there a direct command to check if the delimiter in your file is a tab or a space? And how can they be converted from one to another.
Thanks,
G (4 Replies)
Hi,
I have a space delimited text file but I only want to change the first space to a tab and keep the rest of the spaces intact. How do I go about doing that? Thanks! (3 Replies)
I have a variable sumOfJEOutputFile which is the output file of an SQL command which contains the output of that SQL. The output looks like below:
-----------
58
I am using following code to manipulate the output:
(sed 1,2d $sumOfJEOutputFile > $newTemp1 | sed '$d' $newTemp1)... (4 Replies)
My file looks like
3 33 210.01.10.0 2.1 1211 560 26 45 1298 98763451112 15412323499 INPUT OK
3 233 40.01.10.0 2.1 1451 780 54 99 1876 78787878784 15423210199 CANCEL OK
Aim is to replace the spaces in each line by tab
Used: sed -e 's/ */\t/g'
But I get output like this... (3 Replies)
Discussion started by: sa@@
3 Replies
LEARN ABOUT DEBIAN
paps
PAPS(1) General Commands Manual PAPS(1)NAME
paps - UTF-8 to PostScript converter using Pango
SYNOPSIS
paps [options] files...
DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves
through the pango ft2 backend.
OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is
included below.
--landscape
Landscape output. Default is portrait.
--columns=cl
Number of columns output. Default is 1.
Please notice this option isn't related to the terminal length as in a "80 culums terminal".
--font=desc
Set the font description. Default is Monospace 12.
--rtl Do right to left (RTL) layout.
--paper ps
Choose paper size. Known paper sizes are legal, letter and A4. Default is A4.
Postscript points
Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch.
--bottom-margin=bm
Set bottom margin. Default is 36 postscript points.
--top-margin=tm
Set top margin. Default is 36 postscript points.
--left-margin=lm
Set left margin. Default is 36 postscript points.
--right-margin=rm
Set right margin. Default is 36 postscript points.
--gutter-width=gw
Set gutter width. Default is 40 postscript points.
--help Show summary of options.
--header
Draw page header for each page.
--markup
Interpret the text as pango markup.
--lpi Set the lines per inch. This determines the line spacing.
--cpi Set the characters per inch. This is an alternative method of specifying the font size.
--stretch-chars
Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops
behaviour.
AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>.
This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others).
April 17, 2006 PAPS(1)
08-23-2012
