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Full Discussion: awk - filtering data by if --> into an array
Homework and Emergencies Homework & Coursework Questions awk - filtering data by if --> into an array Post 302690349 by IMPe on Thursday 23rd of August 2012 12:31:20 AM
Old 08-23-2012
Quote:
Originally Posted by Corona688
You haven't answered my question. What relation does your input have with your output? Does the column it ends up in, depend on the first digit of the triplet? Yes? No? Maybe?

This might do what you want... Maybe...

Code:
awk -F"," -v OFS="\t" '{
        L=$10
        N=substr(L, 1, 1)+1;
        $0=$1"-"$2";
        for(N=2; N<=5; N++) $N="-"
        if(L) $N=L } 1' input > output

Hi Corona688!

Thanks for your help. First i will answer the question:
The first triplet-number should be the marker for the coresponding column.
for example:
- triplet 233 according to the timestamp in column 3
- triplet 123 according to the timestamp in column 2
- triplet 433 according to the timestamp in column 5
- triplet 311 according to the timestamp in column 4
Sorry for the slovenly reaktion on your question.
Finally there a two points:
1. I change the code slightly, because i have to change the dateformat
Code:
 awk -F"," -v OFS="\t" '{
                L=$10
                N=substr(L, 1, 1)+1;
                $0=substr($1, 4, 2) "/" substr($1, 1, 2) "/" substr($1, 9, 2)"-"$2;
                for(N=2; N<=4; N++) $N="-"
                if(L) $N=L } 1' input.dat > output.txt

2. The code is working efficently and fast, but the result is
every triplet is written into the last column ..
Code:
01/01/12-00:50  -       -       -       423
01/01/12-01:00  -       -       -       423
01/01/12-01:10  -       -       -       423
01/01/12-01:20  -       -       -       -
01/01/12-01:30  -       -       -       -
01/01/12-01:40  -       -       -       -
01/01/12-01:50  -       -       -       223
01/01/12-02:00  -       -       -       223
....

I try to solve it but without results - can you please help me.

Thanks in advance!
IMPe
 

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LEARN ABOUT LINUX

colrm

COLRM(1)						    BSD General Commands Manual 						  COLRM(1)

NAME

     colrm -- remove columns from a file

SYNOPSIS

     colrm [start [stop]]

DESCRIPTION

     The colrm utility removes selected columns from the lines of a file.  A column is defined as a single character in a line.  Input is read
     from the standard input.  Output is written to the standard output.

     If only the start column is specified, columns numbered less than the start column will be written.  If both start and stop columns are spec-
     ified, columns numbered less than the start column or greater than the stop column will be written.  Column numbering starts with one, not
     zero.

     Tab characters increment the column count to the next multiple of eight.  Backspace characters decrement the column count by one.

ENVIRONMENT

     The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).

EXIT STATUS

     The colrm utility exits 0 on success, and >0 if an error occurs.

SEE ALSO

     awk(1), column(1), cut(1), paste(1)

HISTORY

     The colrm command appeared in 3.0BSD.

BSD
								  August 4, 2004							       BSD
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