Hello Friends
I have three dirs
1. /home/main-bkup
2. /home/bkup-week1
3. /home/bkup-week2
Now we copy backups in 1 initially, then on 1st week we copy few content of 1 into 2 and then run some scripts on that. Then in 2nd week we keep 2 untouched and do the same thing in 3.
So I... (1 Reply)
I am trying to write a script that shows every Friday in a month.
I used
cal $1 $2 | grep -v "^$" | awk '{print $6}'
It doesn't work for the frist week of Friday because calendar command output has some spaces in the first line and awk '{print $6}' doesn't work. Anybody help
me with this... (3 Replies)
Hi all,
It's been a long week and my brain is clearly not functioning right so hopefully someone can help me out here.
I've got a function in a script which just checks if a MySQL database directory exists or not. Code is as follows:
dbCheck2() {
if ;
then {
:
# carry... (4 Replies)
Help please! I need to read the calendar and put the date of the third Friday of each month into a variable for comparison in an "if" statement. How would I do this?
Thnx,
leslie02 (10 Replies)
Freinds,
I need help:
I need to process number of flat files on weekly basis. My source dir will receive flat files regulary at mid night
between 1:00am and 6:00am. When I run my weekly file process it should get only the files which are until last friday
(including friday)and move them in... (1 Reply)
Hi Expert
Please help me to set a cron job schedule,
Ihave a job that run every 3rd Friday of the month at 1030am.
I tried to set up like this, but the job still runs every friday at 1030am.
I want the job to run every 3rd Friday of the month at 1030am only
30 10 15,16,17,18,19,20,21... (2 Replies)
Hello,
I need to find the date of next first Friday of the month and set as a variable in a bash script
ie -
FIRSTFRIDAY=$(date -dfirst-friday +%d)
I know date -dfirst-friday doesn't work, but unsure if I can use this / cal + awk or something else to find the right date of the... (7 Replies)
Discussion started by: summerdays
7 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)