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Top Forums Shell Programming and Scripting how to proceed when curl is finished Post 302689597 by locoroco on Tuesday 21st of August 2012 06:21:55 PM
Old 08-21-2012
Quote:
Originally Posted by Chubler_XL
So is it just $datastring that contains $variables that you need to expand?
yes, just $datastring



Now I have found a solution with your help. I put double quotes around the url, to prevent it from running in the background. Smilie

Code:
string=$(echo "curl -d "'"'$datastring'"'" -b cookie.txt -c cookie.txt -L "\'$url\') 
eval $string > source.html 
teststring=$(awk '/text/' source.html)

---------- Post updated at 12:21 AM ---------- Previous update was at 12:18 AM ----------

By the way, do you or anyone else know an easier way to pass variables to curl?
 

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curl_unescape(3)						  libcurl Manual						  curl_unescape(3)

NAME
curl_unescape - URL decodes the given string SYNOPSIS
#include <curl/curl.h> char *curl_unescape( char *url, int length ); DESCRIPTION
Obsolete function. Use curl_easy_unescape(3) instead! This function will convert the given URL encoded input string to a "plain string" and return that as a new allocated string. All input characters that are URL encoded (%XX where XX is a two-digit hexadecimal number) will be converted to their plain text versions. If the 'length' argument is set to 0, curl_unescape() will use strlen() on the input 'url' string to find out the size. You must curl_free() the returned string when you're done with it. AVAILABILITY
Since 7.15.4, curl_easy_unescape(3) should be used. This function will be removed in a future release. RETURN VALUE
A pointer to a zero terminated string or NULL if it failed. SEE ALSO
curl_easy_escape(3), curl_easy_unescape(3), curl_free(3), RFC 2396 libcurl 7.7 22 March 2001 curl_unescape(3)
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