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Top Forums UNIX for Advanced & Expert Users Need to get the time difference for all the transactions in a day Post 302689157 by agama on Monday 20th of August 2012 09:37:08 PM
Old 08-20-2012
Based on the very small sample, this may work:

Code:
awk '
    /Entering/ { startt[$6, $(NF-2)] = $1 " " $2; next; }
    /Exiting/ { tn = $(NF-2); printf( "TN %s start: %s  end: %s %s\n", tn, startt[$6, tn], $1, $2 ); }
' input-file >output-file

I assumed the thread number, other than for matching, was unimportant.
 

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pnmpsnr(1)                                                    General Commands Manual                                                   pnmpsnr(1)

NAME
pnmpsnr - compute the difference between two portable anymaps SYNOPSIS
pnmpsnr [pnmfile1] [pnmfile2] DESCRIPTION
Reads two PBM, PGM, or PPM files, or PAM equivalents, as input. Prints the peak signal-to-noise ratio (PSNR) difference between the two images. This metric is typically used in image compression papers to rate the distortion between original and decoded image. If the inputs are PBM or PGM, pnmpsnr prints the PSNR of the luminance only. Otherwise, it prints the separate PSNRs of the luminance, and chrominance (Cb and Cr) components of the colors. The PSNR of a given component is the ratio of the mean square difference of the component for the two images to the maximum mean square difference that can exist betwee any two images. It is expressed as a decibel value. The mean square difference of a component for two images is the mean square difference of the component value, comparing each pixel with the pixel in the same position of the other image. For the purposes of this computation, components are normalized to the scale [0..1]. The maximum mean square difference is identically 1. So the higher the PSNR, the closer the images are. A luminance PSNR of 20 means the mean square difference of the luminances of the pixels is 100 times less than the maximum possible difference, i.e. 0.01. SEE ALSO
pnm(5) 04 March 2001 pnmpsnr(1)
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