I'm just starting out in scripting (taking online classes) but I need to know how to clean out (delete) the content of a number of logs. All of the files end in 'trc'. Does anyone have a script or command (SED or AWK) I can use?
Julie (4 Replies)
Is there any way using the sort command to get something like a GROUP BY clause?
I'm trying to sort through race_event records and group them by those individuals that raced together in the same race on the same date at the same track, but i run into a problem when there were days when the track... (6 Replies)
hi,
which Unix/C function can i use to retrieve all group names with a particular group id?
The following C code prints out the group id number of a particular group name:
------------------------------------------------------------------------
#include <stdio.h>
#include <grp.h>
int... (3 Replies)
I wrote script in bash which generates this report:
User1,admin,rep,User2,shell,path1,x1,r1
User2,admin,rep,User7,shell,path1,x1,r1
User3,admin,rep,User4,shell,path1,x1,r1
User4,admin,rep,User3,shell,path1,x1,r1
User5,admin,rep,User1,shell,path1,x1,r1
User6,admin,rep,User5,shell,path1,x1,r1... (6 Replies)
Hi @ all
I'm trying to achive to this problem,
I've a 2-column composed file as the following:
192.168.1.2 2
192.168.1.3 12
192.168.1.2 4
192.168.1.4 3
cpc1-swan1-2-3-cust123.swan.cable.ntl.com 4
192.168.1.3 5
192.168.1.2 10
192.168.1.4 8... (8 Replies)
I have record having 10 fields and each field being printed on a new line, first line cotains name of exchange, 2nd line stock name, third line stock price, etc etc...
now i want to retrieve data only for a particular exchanged and that too only 2nd and 3rd row info...
NSE
RNRL
70
12
1... (1 Reply)
I've this file and need to sort the data in each group
File would look like this ...
cat file1.txt
Reason : ABC
12345-0023
32123-5400
32442-5333
Reason : DEF
42523-3453
23345-3311
Reason : HIJ
454553-0001
I would like to sort each group on the last 4 fileds and print them... (11 Replies)
Hello,
I have a file and i want to sort by third column and extract the three top lines of each group, it is determined by the second column (144, 89, 55, etc).
Could you please help me with the appropiate awk shell script
XLY-XLP 144 0.592772 XLY-XLE 144 0.798121 ... (3 Replies)
JOIN(1) General Commands Manual JOIN(1)NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If one of the file names is the
standard input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Input fields are normally separated spaces or tabs; output fields by space. In this case, multiple separators count as one, and leading
separators are discarded.
The following options are recognized, with POSIX syntax.
-a n In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-v n Like -a, omitting output for paired lines.
-e s Replace empty output fields by string s.
-1 m
-2 m Join on the mth field of file1 or file2.
-jn m Archaic equivalent for -n m.
-ofields
Each output line comprises the designated fields. The comma-separated field designators are either 0, meaning the join field, or
have the form n.m, where n is a file number and m is a field number. Archaic usage allows separate arguments for field designators.
-tc Use character c as the only separator (tab character) on input and output. Every appearance of c in a line is significant.
EXAMPLES
sort /etc/passwd | join -t: -1 1 -a 1 -e "" - bdays
Add birthdays to the /etc/passwd file, leaving unknown birthdays empty. The layout of /adm/users is given in passwd(5); bdays con-
tains sorted lines like
tr : ' ' </etc/passwd | sort -k 3 3 >temp
join -1 3 -2 3 -o 1.1,2.1 temp temp | awk '$1 < $2'
Print all pairs of users with identical userids.
SOURCE
/src/cmd/join.c
SEE ALSO sort(1), comm(1), awk(1)BUGS
With default field separation, the collating sequence is that of sort -b -ky,y; with -t, the sequence is that of sort -tx -ky,y.
One of the files must be randomly accessible.
JOIN(1)