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Top Forums UNIX for Advanced & Expert Users sed: -e expression #1, char 0: no previous regular expression Post 302688751 by Don Cragun on Monday 20th of August 2012 06:07:53 AM
Old 08-20-2012
Quote:
Originally Posted by RudiC
Sorry, disagree. From the bash man page:
Running InduInduIndu's code snippet - using ${#...} to correctly get the member count - fails in the fourth loop,
Code:
++ k=4
++ sed -n //,//p problemid.txt
sed: -e expression #1, char 0: no previous regular expression

indicating that he should limit his loop count to 0 - 2. The first loop works fine:
Code:
++ sed -n /PRS111/,/PRS213/p problemid.txt

Ouch. Yes, you're right. Both bash and ksh use the same notation for setting an indexed array, but bash uses 0 based indexing and ksh uses 1 based indexing. (I guess you can tell that I do most of my shell scripting with ksh. Smilie)
 

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let(1)                                                             User Commands                                                            let(1)

NAME
let - shell built-in function to evaluate one or more arithmetic expressions SYNOPSIS
ksh let arg... DESCRIPTION
ksh Each arg is a separate "arithmetic expression" to be evaluated. EXIT STATUS
The following exit values are returned: 0 The value of the last expression is non-zero. 1 The value of the last expression is zero. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ SEE ALSO
ksh(1), set(1), typeset(1), attributes(5) SunOS 5.10 15 Apr 1994 let(1)
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