08-19-2012
Quote:
Originally Posted by
shyam.sunder91
im supposed to get the result output as Rx signal usr1 but i havnt why so
Are you certain that it isn't being printed? Are you running the binary in the background while trying to send signals to it? If so, depending on your terminal settings, an attempt to write to the terminal could stop the process. Also, note that your printf statements do not have a terminating newline. Perhaps it did print but you missed it? Perhaps the output got lost among other output, such as the shell prompt? Depending on how you called it, perhaps its stdout has been redirected?
Quote:
Originally Posted by
shyam.sunder91
Your code spins needlessly.
while (1); cpu usage will hit 100% and pause() is never reached. You can accomplish your goal without using any cpu between signals:
while (1) pause(); or even
while (pause());
Regards,
Alister
This User Gave Thanks to alister For This Post:
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PAUSE(3) BSD Library Functions Manual PAUSE(3)
NAME
pause -- stop until signal
LIBRARY
Standard C Library (libc, -lc)
SYNOPSIS
#include <unistd.h>
int
pause(void);
DESCRIPTION
Pause is made obsolete by sigsuspend(2).
The pause() function forces a process to pause until a signal is received from either the kill(2) function or an interval timer. (See
setitimer(2).) Upon termination of a signal handler started during a pause(), the pause() call will return.
RETURN VALUES
Always returns -1.
ERRORS
The pause() function always returns:
[EINTR] The call was interrupted.
SEE ALSO
kill(2), poll(2), select(2), setitimer(2), sigsuspend(2)
STANDARDS
The pause() function conforms to ISO/IEC 9945-1:1990 (``POSIX.1'').
HISTORY
A pause() syscall appeared in Version 6 AT&T UNIX.
BSD
June 4, 1993 BSD