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Top Forums Shell Programming and Scripting How to list todays and yesterdays .rej files from a directory? Post 302685687 by pamu on Monday 13th of August 2012 08:30:39 AM
Old 08-13-2012
try this.....

Code:
var_today=$(date "+%b %d")
var_yest=$(date --date="yesterday" "+%b %d")
ls -lrt *.rej | grep "$var_yest" ; ls -lrt *.rej | grep "$var_today"

 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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