Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Replace the nth column date as MM/DD/YYYY
Top Forums Shell Programming and Scripting Replace the nth column date as MM/DD/YYYY Post 302685501 by raj_saini20 on Monday 13th of August 2012 04:05:50 AM
Old 08-13-2012
Code:
awk -F"|" '
{	for(i=3;i<=4;i++)
		{
			split($i,a,"/");
			if(a[1]<10){a[1]="0"substr(a[1],1)};
			if(a[2]<10){a[2]="0"substr(a[2],1)};
			$i=a[1]"/"a[2]"/"a[3]};
			print
}' OFS="|" filename

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
Discussion started by: stringzz
9 Replies

2. Shell Programming and Scripting

converting the date field from dd/mm/yyyy to yyyy/mm/dd

How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix my script will generate text file which have two fields one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
Discussion started by: pareshan
4 Replies

3. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Discussion started by: keyboarder
6 Replies

4. Shell Programming and Scripting

Convert date column as yyyy/mm/dd format

Hi All, I have file like “April 10, 2013”,”raj” “April 29, 2013”,”raj1” Output : “2013/04/10”,”raj” “2013/04/29”,”raj1” Please help me how to do... (9 Replies)
Discussion started by: bmk
9 Replies

5. Shell Programming and Scripting

awk to search for specific line and replace nth column

I need to be able to search for a string in the first column and if that string exists than replace the nth column with "-9.99". AW12000012012 2.38 1.51 3.01 1.66 0.90 0.91 1.22 0.82 0.57 1.67 2.31 3.63 0.00 AW12000012013 1.52 0.90 1.20 1.34 1.21 0.67 ... (14 Replies)
Discussion started by: ncwxpanther
14 Replies

6. Shell Programming and Scripting

How to search and replace string from nth column from a file?

I wanted to search for a string and replace it with other string from nth column of a file which is comma seperated which I am able to do with below # For Comma seperated file without quotes awk 'BEGIN{OFS=FS=","}$"'"$ColumnNo"'"=="'"$PPK"'"{$"'"$ColumnNo"'"="'"$NPK"'"}{print}' ${FileName} ... (5 Replies)
Discussion started by: Amit Joshi
5 Replies

7. Shell Programming and Scripting

awk search and replace nth column by using a variable.

I am passing a variable and replace nth value with the variable. I tried using many options in awk command but unable to ignore the special characters in the output and also unable to pass the actual value. Input : "1","2","3" Output : "1","1000","3" TempVal=`echo 1000` Cat... (2 Replies)
Discussion started by: onesuri
2 Replies

8. Shell Programming and Scripting

Search term in nth field and replace kth column

Hi, I have a text file which looks like this a.txt A,12,Apple,Red B,33,Banana,Yellow C,66,Sky,Blue I need to search for a particular field(s) in particular column(s) and for that matching line need to replace the nth column. Sample scenario 1: Search for 66 in second field and Sky in... (5 Replies)
Discussion started by: wahi80
5 Replies

9. Shell Programming and Scripting

Replace Value of nth Column of Each Line Using Array

Hello All, I am writing a shell script with following requirement: 1. I have one input file as below CHE01,A,MSC,INO CHE02,B,NST,INC CHE03,C,STM,INP 2. In shell script I have predefined array as below: Array1={A, B, C} Array2= {U09, C04, A054} (6 Replies)
Discussion started by: angshuman
6 Replies

10. UNIX for Beginners Questions & Answers

awk script to extract a column, replace one of the header and replace year(from ddmmyy to yyyy)

I have a csv which has lot of columns . I was looking for an awk script which would extract a column twice. for the first occurance the header and data needs to be intact but for the second occurance i want to replace the header name since it a duplicate and extract year value which is in ddmmyy... (10 Replies)
Discussion started by: Kunalcurious
10 Replies

LEARN ABOUT SUSE

html::formattext

HTML::FormatText(3)					User Contributed Perl Documentation				       HTML::FormatText(3)

NAME

       HTML::FormatText - Format HTML as plaintext

SYNOPSIS

	require HTML::TreeBuilder;
	$tree = HTML::TreeBuilder->new->parse_file("test.html");

	require HTML::FormatText;
	$formatter = HTML::FormatText->new(leftmargin => 0, rightmargin => 50);
	print $formatter->format($tree);

DESCRIPTION

       The HTML::FormatText is a formatter that outputs plain latin1 text.  All character attributes (bold/italic/underline) are ignored.
       Formatting of HTML tables and forms is not implemented.

       You might specify the following parameters when constructing the formatter:

       leftmargin (alias lm)
	   The column of the left margin. The default is 3.

       rightmargin (alias rm)
	   The column of the right margin. The default is 72.

SEE ALSO

       HTML::Formatter

COPYRIGHT

       Copyright (c) 1995-2002 Gisle Aas, and 2002- Sean M. Burke. All rights reserved.

       This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself.

       This program is distributed in the hope that it will be useful, but without any warranty; without even the implied warranty of
       merchantability or fitness for a particular purpose.

AUTHOR

       Current maintainer: Sean M. Burke <sburke@cpan.org>

       Original author: Gisle Aas <gisle@aas.no>

perl v5.12.1							    2004-06-02						       HTML::FormatText(3)
All times are GMT -4. The time now is 05:08 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy