What the logic I am applying is splitting each file into a array(now array consists with 3 elements) and then concatenating the first elements from array.
For eg.
data1.htm.orig
Code:
@arr = split(/\./,$file1); ## here 3 elements will be splitted
$new_file = $arr[0].$arr[1]; ## new_file becomes data1.htm
Could you please correct if I am wrong and guide me in right direction?
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Hi ALL,
I'm new to this forum.
Thanks and congrats to all for their great efforts building this site simply superb for all unix administrators.
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Discussion started by: cmccabe
4 Replies
LEARN ABOUT LINUX
prename
RENAME(1) Perl Programmers Reference Guide RENAME(1)NAME
rename - renames multiple files
SYNOPSIS
rename [ -v ] [ -n ] [ -f ] perlexpr [ files ]
DESCRIPTION
"rename" renames the filenames supplied according to the rule specified as the first argument. The perlexpr argument is a Perl expression
which is expected to modify the $_ string in Perl for at least some of the filenames specified. If a given filename is not modified by the
expression, it will not be renamed. If no filenames are given on the command line, filenames will be read via standard input.
For example, to rename all files matching "*.bak" to strip the extension, you might say
rename 's/.bak$//' *.bak
To translate uppercase names to lower, you'd use
rename 'y/A-Z/a-z/' *
OPTIONS -v, --verbose
Verbose: print names of files successfully renamed.
-n, --no-act
No Action: show what files would have been renamed.
-f, --force
Force: overwrite existing files.
ENVIRONMENT
No environment variables are used.
AUTHOR
Larry Wall
SEE ALSO mv(1), perl(1)DIAGNOSTICS
If you give an invalid Perl expression you'll get a syntax error.
BUGS
The original "rename" did not check for the existence of target filenames, so had to be used with care. I hope I've fixed that (Robin
Barker).
perl v5.12.4 2011-08-10 RENAME(1)
08-07-2012
