awk calculation automatically rounding off the output
I have some calculation in my script which is similar to the below example . I find that sometimes when using large decimal digits, the output gets automatically rounded off and it is affecting the program. I am not able to understand what is happening here..
prints:
Where is the decimals points in "d" . And if it got rounded off, why is the decimals appearing in "result1"
Could you help me understand what really is happening ? How can i make sure that the decimals does not get rounded off automatically?
Last edited by zaxxon; 08-07-2012 at 07:39 AM..
Reason: code tags
Hallo all,
I have a script which creates an output ... see below:
root@a7germ:/tmp/pax > cat 20061117.txt
523.047
521.273
521.034
517.367
516.553
517.793
513.114
513.940
I would like to use awk to calculate the (a)total sum of the numbers (b) The average of the numbers.
Please... (4 Replies)
Hello
I am getting this very annoying issue in awk:
awk '{a=12825;b=a*1.25; print b}' test
16031.2
Thing is the multiplication result is wrong... Result should be 16031.25.
I think the issue only happens on bigger numbers.
What can I do to get passed this?
Thanks by advance (3 Replies)
Hi Friends,
I am trying to round following number.
0.07435000
echo "0.07435000"|awk '{printf "%s\n",$1*100}'|awk '{printf "%.2f\n",$1}'
It returns: 7.435
It should return: 7.44
Any suggestion please?
Thanks,
Prashant (2 Replies)
Hi,
I have managed to round up numbers by using the following command:
echo "5.54" | awk '{printf "%.0f\n", $1}'
result
6
How can I round up all the numbers in a column in a file and print the lines with the new calculated totals?
Thanks, (3 Replies)
I had a person bring an interesting problem to me that appears to involve some sort of rounding inside awk. I've verified this with awk and nawk on Solaris as well as with gawk 3.1.5 on a Linux box.
The original code fragment he brought me was thus:
for (index=0; index < 1; index=index+.1)
... (4 Replies)
Hi guys,
could someone throw some light on the following behaviour of printf (I'll start with info about the system and the tool/shell/interpreter versions)?:
$ uname -a
Linux linux-86if.site 3.1.0-1.2-desktop #1 SMP PREEMPT Thu Nov 3 14:45:45 UTC 2011 (187dde0) x86_64 x86_64 x86_64... (9 Replies)
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)
I am trying to run the awk below. My question is when I split the input, then run anotherawk to perform a calculation using that splitas the input there are no issues. When I try to combine them the output is not correct, is the split not working or did I do it wrong? Thank you :).
input
... (8 Replies)
The awk below is close but I can't seem to fix it to produce the desired output. Thank you :).
current awk with output
awk '{c1++; c2+=($2)}
END{for (e in c1) print e, c1, c2}' input
EFCAB5 2 50
USH2A 2 19
desired... (8 Replies)
In the below awk, I am trying to calculate percent for a given id. It is very close the problem is when the # being used in the calculation is zero. I am not sure how to code this condition into the awk as it happens frequently. The portion in italics was an attempt but that lead to an error. Thank... (13 Replies)
Discussion started by: cmccabe
13 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)