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Top Forums UNIX for Dummies Questions & Answers why output consists of 3 values Post 302681871 by FUTURE_EINSTEIN on Saturday 4th of August 2012 05:41:04 PM
Old 08-04-2012
why output consists of 3 values

Hi there if I have a file called an411
which contains the folowing information
152.78.74.111 [13/Feb/2011:06:52:00 +0000] "GET /datafeed.php HTTP/1.1" 200 2826
152.78.74.211 [13/Feb/2011:06:53:00 +0000] "GET /index.html HTTP/1.1" 200 1190
152.78.74.121 [13/Feb/2011:06:55:00 +0000] "GET / HTTP/1.1" 200 3000
and I want to ouput the number of bytes of the record that contains pattern.
The code:
Code:
 grep '[datafeed.php]' an411 | cut -d" " -f8

returns
2826
1190
3000
Can anyone explain me why it returns 3 values. I think it should return only one because grep matches pattern doesn't it?
Any help Smilie
Thanks in advance Smilie
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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