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Homework and Emergencies Homework & Coursework Questions Help with exit, grep, temporary files, awk Post 302680337 by methyl on Wednesday 1st of August 2012 05:34:18 PM
Old 08-01-2012
Quote:
I do not understand how/why the following code is used. Please do not simply refer me to the man pages since I have already reviewed them extensively. Thank you.

exit 2 , exit 3, exit 0
I understand the basics of why the exit command is used, but I still don't understand what the significance/meaning of exit 2, exit 3, and exit 0 are.
The exit code used to provide a simple reply to the calling script or process as to the result of executiing the script. Code zero means it worked. Other codes are chosen by the script writer.
A calling script will find that the value of the exit code is in the Environment Variable $? .
Code:
# Illustration of using the exit code by storing it in a named variable
# We store it in a variable because the next command will change the value!
./scriptname ; RESULT=$?
if [ ${RESULT} -gt 0 ]
then
       echo "Script failed with exit code: ${RESULT}"
fi


Quote:
The creation (and later deletion) of a temporary file
I understand that creation of the temporary file is used to print the contents of the following commands within that file so the grep command can be used to calculate our echoed results that we want, BUT, isn't there a better way to do it so we don't have to create/delete a file?
ls -log "$1" | awk '{print $1}' | grep -v total > $TF
I understand how the first part is piped to the awk, but I do not understand how the awk command is printing only the first column of information.
As far as the "grep -v total" goes, am I correct in that that command basically says to print to screen only those lines within that first column that do NOT contain the word "total"?
If you want to make multiple enquiries on a data selection, a temporary file is the best and most efficient solution. The awk looks for any white space between fields and outputs the first field ($1). The grep -v excludes the Total line from ls. It can be improved with -iv as some ls commands output in upper and lower case.
Code:
ls -log "$1" | awk '{print $1}' | grep -iv "total" > $TF


Code:
f_count=$(grep -c "-........." $TF)
I do not understand why this will not work, however, it also doesn't seem like the best way to accomplish counting the number of files within the specified directory.

Sorry, I don't understand this command. Other posters will!
I'd have done it with:
Code:
f_count=$(grep -c \^\- $TF)


Last edited by methyl; 08-01-2012 at 06:53 PM.. Reason: formatting fun; correct ls -1 line
 

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