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Full Discussion: find command with -exec
Top Forums Shell Programming and Scripting find command with -exec Post 302680153 by Don Cragun on Wednesday 1st of August 2012 10:43:05 AM
Old 08-01-2012
Your code executes ls for each file that is newer than the file named by <file_name> and if one of those files is a directory, you'll list the contents of that directory instead of the directory itself.

I think you want something like:
Code:
ls -lrt | awk -v file=<file_name> 'BEGIN        {found=0}
        found==1        {print}
        $9 == file      {found=1}'

Note, however, that this will not work if the file name indicated by <file_name> contains any whitespace characters or if any filename older than that file has a name that starts with that name and is immediately followed by a whitespace character. I assume you can work around this limitation.
 

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