Possible to use /usr/bin/watch to call a function?
I want to have a script both define functions and have the ability to run an external program calling one of them. This is the simplified construct:
Code:
#!/bin/bash
foo() {
echo "this is foo"
}
bar() {
echo "this is bar"
}
case "$1" in
one)
foo
;;
two)
export bar
/usr/bin/watch bar
;;
*)
echo $0 "{one|two}"
exit 0
;;
esac
So if I invoke /path/to/script one the foo function runs and it exits as expected. I want to ability to run the bar function as if it were a stand-alone program via `/usr/bin/watch bar` but this doesn't work as expected.
Code:
$ /path/to/script two
Every 2.0s: bar Mon Jul 30 02:16:25 2012
sh: bar: command not found
How can I accomplish it?
---------- Post updated at 03:18 AM ---------- Previous update was at 02:16 AM ----------
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Discussion started by: AntumDeluge
2 Replies
LEARN ABOUT CENTOS
libtalloc_stealing
libtalloc_stealing(3) talloc libtalloc_stealing(3)NAME
libtalloc_stealing - Chapter 2: Stealing a context
Stealing a context
Talloc has the ability to change the parent of a talloc context to another one. This operation is commonly referred to as stealing and it
is one of the most important actions performed with talloc contexts.
Stealing a context is necessary if we want the pointer to outlive the context it is created on. This has many possible use cases, for
instance stealing a result of a database search to an in-memory cache context, changing the parent of a field of a generic structure to a
more specific one or vice-versa. The most common scenario, at least in Samba, is to steal output data from a function-specific context to
the output context given as an argument of that function.
struct foo {
char *a1;
char *a2;
char *a3;
};
struct bar {
char *wurst;
struct foo *foo;
};
struct foo *foo = talloc_zero(ctx, struct foo);
foo->a1 = talloc_strdup(foo, "a1");
foo->a2 = talloc_strdup(foo, "a2");
foo->a3 = talloc_strdup(foo, "a3");
struct bar *bar = talloc_zero(NULL, struct bar);
/* change parent of foo from ctx to bar */
bar->foo = talloc_steal(bar, foo);
/* or do the same but assign foo = NULL */
bar->foo = talloc_move(bar, &foo);
The talloc_move() function is similar to the talloc_steal() function but additionally sets the source pointer to NULL.
In general, the source pointer itself is not changed (it only replaces the parent in the meta data). But the common usage is that the
result is assigned to another variable, thus further accessing the pointer from the original variable should be avoided unless it is
necessary. In this case talloc_move() is the preferred way of stealing a context. Additionally sets the source pointer to NULL,
thus.protects the pointer from being accidentally freed and accessed using the old variable after its parent has been changed.
Version 2.0 Tue Jun 17 2014 libtalloc_stealing(3)