Creating an array Post: 302674989

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Top Forums UNIX for Dummies Questions & Answers Creating an array Post 302674989 by Lem on Saturday 21st of July 2012 05:59:56 AM

07-21-2012

Registered User

Quote:

Originally Posted by jrymer

Code:

#!/bin/bash
ARRAY=one two three

This is the only wrong one. It assigns only 'one' to the variable ARRAY... then calls 'two' as a command with 'three' as its parameter.

Quote:

When I do this I receive the error
: two: not found
and
: Bad substitution

Bad sustitution? Where does it come from?
Oh! This is sh speaking, not bash (in sh you don't have arrays!)
Somehow, you're using sh and not bash. In sh there aren't arrays, something like

Code:

${ARRAY[0]}

is indeed a bad susbstitution, and there's no declare builtin command.

Quote:

Code:

ARRAY=(one two three)
ARRAY=( one two three )
ARRAY=( 'one' 'two' 'three' )
ARRAY=('one' 'two' 'three')

These above are all fine... in bash of course.

Quote:

I've tried it with declare -a out front too, and I get
: declare: not found

Somehow you're using sh, not bash.
Declare is an internal bash command. If you were using bash, it would be found. Better: it wouldn't need to be looked for: it'd be already available, it'd be already there.
Since you're using sh, which doesn't know what 'declare' is, you get an error.

Why are you using sh and not bash? I don't know. Maybe some more info would help.
--
Bye

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