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Full Discussion: Creating an array
Top Forums UNIX for Dummies Questions & Answers Creating an array Post 302674339 by jrymer on Thursday 19th of July 2012 11:52:11 AM
Old 07-19-2012
Creating an array

I am having trouble creating an array, I've tried everything google gives me but it won't work, and it seems as though it should. Using Ubunto 12.04 and bash.

Code:
#!/bin/bash
ARRAY=one two three
echo ${ARRAY[0]}

When I do this I receive the error
: two: not found
and
: Bad substitution

When I use parenthesis like so...

Code:
#!/bin/bash
ARRAY=(one two three)
echo ${ARRAY[0]}

and

Code:
#!/bin/bash
ARRAY=( one two three )
echo ${ARRAY[0]}

I get the error
: Syntax error: "(" unexpected

When I try...

Code:
#!/bin/bash
ARRAY=( 'one' 'two' 'three' )
 echo ${ARRAY[0]}

and
Code:
#!/bin/bash
ARRAY=('one' 'two' 'three')
  echo ${ARRAY[0]}

I get the unexpected "(" error

I've tried it with declare -a out front too, and I get
: declare: not found

I've also tried variations of...

Code:
#!/bin/bash
ARRAY[1]=two
echo ${ARRAY[1]}

Getting the error ARRAY=[1] not found
Bad substitution

I've even changed the echo command to
Code:
echo ${ARRAY[*]}

I've tried every combination of almost everything EXCEPT iterating through a loop but I don't see why that would work and a simple echo would not.

The ultimate goal is to store all the months of the year in an array, like 2012-01-01 and so forth.

Also I formatted it using dos2unix and it didn't fix it.

I feel as thought his is very easy and should not be happening, but if that is not the case and I have made a careless error PLEASE humble me.

Thanks

Last edited by jrymer; 07-19-2012 at 01:13 PM..
 

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