I'm not sure exactly when I've seen such a rubbish piece of code You are passing each element of that convoluted find command as a filename to grep. That's where the error is coming from - there are just too many filenames to pass as arguments.
Here's my take, which might also be a mis-interpretation of your intentions:
Hi
I executed the code
for file in `ls pdb*.ent`
do
new_name=`echo $file | sed 's/^pdb//;s/.ent/.txt/'`
mv $file $new_name
done
Its giving error at ' ls pdb*.ent' argument list too long
i have around 150000 entries
please help
Thank you (6 Replies)
I have a wrote a script which consits of the below line.. Below of this script I'm getting this error "ksh: /usr/bin/ls: arg list too long"
The line is
log_file_time=`ssh -i $HOME/.ssh/id_rsa -q $i ls -lrt /bp/karthik/test/data/log/$abc*|tail -1|awk '{print $8}'`
And $abc alias is as "p |... (1 Reply)
Hi guys
Following command results in
sed -i 's/#/\\#/g' /home/test/sqlstents*
-bash: /bin/sed: Argument list too long
Please help me solve it.. is there any other way i can do this?.. thanks (4 Replies)
I have a huge set of files (with extension .common) in my directory around 2 million. When I run this script on my Linux with BASH, I get /bin/awk: Argument list too long
awk -F'\t' '
NR == FNR { a=NR }
NR != FNR {
sub(".common", "", FILENAME)
print a, FILENAME, $1
}
'... (1 Reply)
Dear Friends,
The following script processes a 14508 lines log file.
#!/bin/sh
while read line
do
d=`sed 's/* - * \*\/*\/* *\)\] .*/\1/' | tr '/' ' ' | sed 's/\(*\):\(*\)/\1 \2/'`
y=`date -d "${d}" "+%Y%m%d%H%M%S"`
echo "${y}"
done
While running the above script, I am... (4 Replies)
Dear Experts,
I have a list of 10K files in a directory. I am not able to execute any commands lile ls -lrt, awk, sed, mv, etc........
I wanna execute below command and get the output. How can I achieve it?? Pls help.
root# awk -F'|' '$1 == 1' file_20120710* | wc -l
/bin/awk: Argument list... (2 Replies)
Hi I am using find command --
find "directory1" -type f | xargs -i mv {} "directory2"
to avoid above argument list too long problem.
But, issue i am facing is directory1 is having subdirectories due to this i am facing directory traversal problem as i dont want to traverse subdirectories... (9 Replies)
Hi all,
I am using GNU sed (named gsed under macports) in OSX. I have a directory with a series of files named pool_01.jpg through pool_78802.jpg. I am trying to use this command to rename the files to their checksum + extension.
md5sum * | gsed -e 's/\(*\) \(.*\(\..*\)\)$/mv -v \2 \1\3/e'
... (3 Replies)
Hi All,
This question has been asked many times, but my problem is slightly different.
In my shell script i am connecting to oracle database and loading the results to .dat file. This .dat file is later used to create to .xls file Some times the size of .dat file becomes more than 120000... (8 Replies)
Hi Team,
Here's the situation.
I have approximately 300000 to 500000 jpg files in /appl/abcd/work_dir
mv /appl/abcd/work_dir /appl/abcd/process_dir
The above move command will work if the jpg files count is close to 50000 (not sure). If the count is less this mv command holds good. But if... (14 Replies)
Discussion started by: kmanivan82
14 Replies
LEARN ABOUT BSD
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)
07-17-2012
You are passing each element of that convoluted find command as a filename to grep. That's where the error is coming from - there are just too many filenames to pass as arguments.