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Top Forums Shell Programming and Scripting using awk to get specific section of lines in logs Post 302672933 by SkySmart on Tuesday 17th of July 2012 09:32:42 AM
Old 07-17-2012
using awk to get specific section of lines in logs

i have a log file that has the date and time that looks like this:

Code:
Wed Jun 28 15:46:21 2012 test failed tailed passed passed not error panic


what we want to focus on is the first 5 columns because they contain the date and time.

the date and time can be anywhere on the line. in this particular case, the date and time is at the beginning of the line. my question is, what happens if it is somewhere else on that line? how can i make it so that when i run a one liner awk command, it finds the date and time wherever it is on the line?

OS: linux and sunos
shell: bash
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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